Answer:
The flowering population is in Hardy Weinberg equilibrium.
Step by Step Explanation:
Total initial population size = 60
As both the populations are homozygous so the frequency of alleles will be,
P = 80/120= 0.66
q = 40/120= 0.33
The predicted frequencies for genotypes once the population has reached Hardy-Weinberg
p2 = 0.4356
2pq= 0.4356
q2 = 0.1089
The number of plants with each type of flower in a papulation of 420 is,
Homozygous dominant= 185
heterozygous= 185
Homozygous recessive= 50
Chi square analysis:
The observed values for red-flowered plants, pink-flowered plants, and white-flowered plants are not significantly different from the expected values predicted by Hardy Weinberg equilibrium.
Phenotype observed(o) expected (e) (o-e)2/e
Red 178 185 0.26
Pink 190 185 0.135
White 52 50 0.08
chi-square = 0.474
With 2 degree of freedom this chi-square gives a p value of 0.7 - 0.8, which is not significant.
A because radon and neon are colorless and calcium is silvery-white.
Answer:
Different parts of the DNA are activated or used.
Explanation:
Different parts of the DNA can be turned "off" or "on" based on the needs to create the certain cell.
