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iVinArrow [24]
3 years ago
11

You are running a fuel economy study. One of the cars you find is blue. can travel 35 1/2 miles on 1 1/4 gallons of gasoline. An

other car is red. It can travel 27 1/5 miles on 4/5 gallons of gasoline.
1) What is the unit rate for miles per gallon for the blue car?

2) What is the unit rate for miles per gallon for the red car?

3) Which car could travel the greater distance on 1 gallon of gasoline?
Mathematics
2 answers:
IgorLugansk [536]3 years ago
8 0

Answer:

1) 28.4 miles per gallon

2) 34 miles per gallon

3) the red car

Step-by-step explanation:

We have the following information:

  • <em>Blue car:</em>

<em>Travels 35 1/2 miles on 1 1/4 gallons of gasoline</em>

  • <em>Red car:</em>

<em>Travels 27 1/5 miles on 4/5 gallons of gasoline</em>

<em />

We want to know the unit rate for miles per hour, and to do it we have to divide the miles they travel by the gallons each car uses:

  • Blue car:

(35 1/2) / (1 1/4) = 28.4 miles per gallon

  • Red car:

(27 1/5) / (4/5) = 34 miles per gallon

The red car travels greater distance with 1 gallon of gasoline

kirza4 [7]3 years ago
8 0
Blue car :
(35 1/2) / (1 1/4) =
(71/2) / (5/4) =
71/2 * 4/5 =
142/5 =
28.4 miles per gallon <=== unit rate for blue

red car : 
(27 1/5) / (4/5) =
(136/5) / (4/5) =
136/5 * 5/4 =
136/4 =
34 miles per gallon <=== unit rate for red

so the red car can travel a greater distance on 1 gallon

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Can someone help me with this worksheet please!!!!
Marat540 [252]

(1) The missing term in the sequence, a₁₂  = 0.8.

(2) The missing term in the sequence, a₈ = 102.5.

(3) The missing term in the sequence, a₈ = 111.

(4) The missing term in the sequence, a₁₂ = -19.

(5) The missing term in the sequence, a₁₂ = 94.

(6)  The missing term in the sequence, a₆ = 40.

(7)  The missing term in the sequence, a₃₆ = -52.

(8)  The missing term in the sequence, a₂₁ = -58.

<h3>Missing term of the sequence</h3>

The missing term in the sequence is determined as follows;

Tₙ = a + (n - 1)d

<h3>1.0 a₄ = 18.4 and a₅ = 16.2, a₁₂ = ?</h3>

T₄ = a + 3d

18.4 = a + 3d  ---(1)

T₅ = a + 4d

16.2 = a + 4d  ---(2)

subtract (1) from (2)

-2.2 = d

18.4 = a + 3(-2.2)

a = 25

a₁₂  = a + 11d

a₁₂  = 25 + 11(-2.2)

a₁₂  = 0.8

<h3>2.0 a₂ = 57.5 and a₅ = 80, a₈ = ?</h3>

a₂ = a + d

57.5 = a + d -- (1)

a₅ = a + 4d

80 = a + 4d  --- (2)

solve (1) and (2)

d = 7.5

a = 50

a₈ =  a + 7d

a₈ = 50 + 7(7.5)

a₈ = 102.5

<h3>3.0 a₁₀ = 141 and a₁₃ = 186, a₈ = ?</h3>

a₁₀ = a + 9d

141 = a + 9d --- (1)

a₁₃ = a + 12d

186 = a + 12d --- (2)

Subtract (1) from (2)

d = 15

a = 6

a₈ = a + 7d

a₈ = 6 + 7(15)

a₈ = 111

<h3>4.0 a₂₂ = -49 and a₂₅ = -58, a₁₂ = ?</h3>

a₂₂ = a + 21d

-49 = a + 21d ---- (1)

a₂₅ = a + 24d

-58 = a + 24d --- (2)

subtract (1) from (2)

d = -3

a = 14

a₁₂ = a + 11d

a₁₂ = 14 + 11(-3)

a₁₂ = -19

<h3>5.0 a₄ = -2 and a₈ = 46, a₁₂ = ?</h3>

a₄ = a + 3d

-2 = a + 3d --- (1)

a₈ = a + 7d

46 = a + 7d ---- (2)

Subtract (1) from (2)

d = 12

a = -38

a₁₂ = a + 11d

a₁₂ = -38 + 11(12)

a₁₂ = 94

<h3>6.0 a₉ = 64 and a₁₂ = 88, a₆ = ?</h3>

a₉ = a + 8d

64 = a + 8d --- (1)

a₁₂ = a + 11d

88 = a + 11d --- (2)

Subtract (1) from (2)

d = 8

a = 0

a₆ = a + 5d

a₆ = 0 + 5(8)

a₆ = 40

<h3>7.0 a₂₀ = -4 and a₂₃ = -13, a₃₆ = ?</h3>

a₂₀ = a + 19d

-4 = a + 19d ---- (1)

a₂₃ = a + 22d

-13 = a + 22d --- (2)

Subtract (1) from (2)

d = -3

a = 53

a₃₆ = a + 35d

a₃₆ = 53 + 35(-3)

a₃₆ = -52

<h3>8.0 a₂₈ = 5 and a₃₃ = 50, a₂₁ = ?</h3>

a₂₈ = a + 27d

5 = a + 27d ---- (1)

a₃₃ = a + 32d

50 = a + 32d --- (2)

Subtract (1) from (2)

d = 9

a = -238

a₂₁ = a + 20d

a₂₁ = -238 + 20(9)

a₂₁ = -58

Learn more about arithmetic progression here: brainly.com/question/6561461

#SPJ1

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