Question

Integers is

Answer 1

Answer:

See below

Step-by-s.ep explanation:

6. Let the 3 integers be k-2, k and k+2.

So k(k+2)-k(k-2) = 28

k^2 + 2k - k^2 + 2k = 28

4k = 28

k = 7.

So the 3 integers are 5, 7 and 9.