Answer:
Option A is the correct option.
Explanation:
Because Dress4Win is the online web organization that asked to the consultant to advice that type of machines that they want to expand their server for those application which perform the work of the mapping on the basis of the premises physical hardware cores and also in the clouds softwares that is nearest machines types of RAM.
Answer:
Decoding is the technique used to convert an electrical signal into an understandable message. This process is used in receiver side.
Explanation:
In telecommunication, Decoder is used to to interpret the message sent by transmitter in to an understandable message. This process is called decoding
<span>The answer is Ten. Substituting numbers for letters, available selections are 111, 112, 113, 122, 123, 133, 222, 223, 233, 333. Note that, for example, 112, 121, and 211 are considered as the same selection.
</span>AAA, BBB, CCC, <span>AAB, AAC, </span><span>BBC, </span><span>ABB, ACC, </span><span>CCB & ABC.</span>
Answer:
Nfc relay attack
Explanation:
The NFC relay attack occurs when data is extracted by an attacker who puts himself in the middle of two parties having a communication with each other. As the message gets to a party, the attacker gets it and modifies it to their taste then passes it on.
This attacker in this question is extracting data by establishing communication between end user devices and reader in the kiosk
<u>Answer:</u>
<em>void main ( ) </em>
<em> { </em>
<em> int counter; </em>
<em> cout<<""Even numbers between 1 to 20 are:""<<endl ; </em>
<em> //Method 1
</em>
<em> for (counter = 1; counter <= 20; counter++) </em>
<em> { </em>
<em> if ( counter%2 == 0) </em>
<em> {
</em>
<em> cout<<counter<<""\t""<<endl ; </em>
<em> } </em>
<em> } </em>
<em>//Method 2 – simplest one
</em>
<em>for (counter = 2; counter <= 20;) </em>
<em> { </em>
<em> cout<<counter<<""\t""<<endl ; </em>
<em>counter = counter + 2;
</em>
<em> </em>
<em> }
</em>
<em>
</em>
<em> return 0; </em>
<em>}
</em>
<u>Explanation:</u>
In this, Method 1 runs a for loop and check whether each number is divided by 2. If yes, then printed otherwise it is skipped.
In the second method, it runs for loop only for even numbers. <em>This is obtained by incrementing the counter by 2.
</em>
