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34kurt
3 years ago
14

The sum of 6 consecutive even number is 126. what is the fourth number in the sequence

Mathematics
1 answer:
bulgar [2K]3 years ago
5 0

let's start off by keeping in mind that, if you multiply any integer by 2, regardless of what that integer is, you will always get an EVEN integer, say 13 * 2 = 26, or 18 * 2 = 36 and so on.

let' see a few consecutive even integers

2, 4, 6, 8, 10, 12 , 14..............

notice, to get another one from any of them, we can simply hop back or forwards twice, namely  8 ± 2, gives us 6 and 10.

so let's use for our first even integer say "2a".

that simply means our next even integer can just be 2a + 2

and we add 2 again and so on to get all 6 even integers.

now, we know they add sum up to 126.


\bf \stackrel{1st}{(2a)}+\stackrel{2nd}{(2a+2)}+\stackrel{3rd}{(2a+4)}+\stackrel{4th}{(2a+6)}+\stackrel{5th}{(2a+8)}+\stackrel{6th}{(2a+10)}~~=~~126
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
12a+30=126\implies 12a=96\implies a=\cfrac{96}{12}\implies \boxed{a=8}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\stackrel{4th}{2(8)+6}\implies 22

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fiasKO [112]
Easy I guess ..
I ll try to help ..
Here we go ..
The cards you have is N
The cards he has is n
<span>you have 3 times the number of cards he has
This means N=3n
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3 years ago
What is the explicit equation for f(0)=8; f(×)=f(×-1)*3
andriy [413]

Hello from MrBillDoesMath!

Answer:

f(x) = 8 * 3^x


Discussion:

x = 0:      f(x) = 8

x = 1:       f(1) = f(0) * 3 = 8*3

x = 2:      f(2) = f(2-1)*3 = f(1) * 3 = (8*3)*3 = 8 * 3^2

x=3 :       f(3) = f(3-1)*3 = f(2)*3 = (8 * 3^2) * 3 = 8 * 3^3

Based on this we guess that

f(x) = 8 * 3^x


Thank you,

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4 0
3 years ago
Describe the process of rounding a number to the nearest thousand
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Say you have the number:

3,347

You can round it to the nearest thousand by figuring out whether 347 turns out to be closer to 0 or 1,000. If it's closer to 0, you round to the nearest thousand by producing the result 3,000. Since 347 is closer to 0, it would be incorrect to round the number 3,347 to the nearest thousand by producing the result 4,000.

In this case you round to the nearest thousand by producing the result 3,000.
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but since \sqrt{f(x,y,z)} and f(x,y,z) share critical points, we can instead consider the problem of optimizing f(x,y,z) subject to x-2y+3z=6.

The Lagrangian is

L(x,y,z,\lambda)=x^2+(y-2)^2+(z-4)^2+\lambda(x-2y+3z-6)

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L_x=2x+\lambda=0\implies x=-\dfrac\lambda2
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Step-by-step explanation:

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