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algol [13]
3 years ago
8

PLEASE HELP QUESTION IN PHOTO

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
8 0

Answer:it hink the answer is 10 cause you can add 8+2 i think

Step-by-step explanation:

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4

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What is 3r³/2r<br>how do I go about solving it <br>thanks​
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Answer:

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Step-by-step explanation:

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Need help finding the area of the shaded region. Round to the nearest tenth. Need help ASAP
Sergio [31]

Answer:   294.4 m²

<u>Step-by-step explanation:</u>

Separate the shaded region into two parts:

  1. The section containing the central angle of 230° (360° - 130°)
  2. The triangle with sides 11.1, 11.1 & 20.12 (use Law of Cosines)

1.\ Area(A)=\pi\ r^2\ \bigg(\dfrac{\theta}{360}\bigg)\\\\\\.\qquad \qquad =\pi(11.1)^2\bigg(\dfrac{230}{360}\bigg)\\\\\\.\qquad \qquad =247.3

2.\ \text{Use Law of cosines to find the length of the third side.}\\\text{ Then use Heron's formula to find the Area of the triangle.}\\\\s=\dfrac{11.1+11.1+20.12}{2}=21.16\\\\\\A=\sqrt{s(s-a)(s-b)(s-c)}\\\\.\ =\sqrt{21.16(21.16-11.1)(21.16-11.1)(21.16-20.12)}\\\\.\ =\sqrt{2227}\\\\.\ =47.1

Area of shaded region = Area of (1) + Area of (2)

                                      =    247.3     +      47.1

                                      =               294.4

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3 years ago
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Simplify.
otez555 [7]
The answer to the question is C.
6 0
3 years ago
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