Answer:
it is 32
Step-by-step explanation:
you multipy 8 buy 4 =32
Answer:
Step-by-step explanation:
This is a parabola shaped like a U.
The minimum value is at (-2, -3).
Find the zeroes:
(x + 2)^2 = 3
Find the zeroes:
x + 2 = +/- √3
x = +/-√3 - 2
x = -0.27, -3.73.
So the graph cuts the x axis at (-0.27, 0) and (-3.73, 0)
when x = -4 , f(x) = 1 and when x = 1, f(x) = 6.
So you can now draw the curve through these 5 points and it will be shaped like a U, symetrical about the line x = -2
Answer:
Bob drove from home to work at 75 mph. After work the traffic was heavier, and he drove home at 40 mph. His driving time to and from work was 1 hour and 9 minutes. How far does he live from his job?
=================
Avg speed for the round trip = 2*75*40/(75+40) = 6000/115 = 1200/23 mi/hr
RT distance = 1200/23 * 69 minutes * 1 hr/60 mins =
= 60 miles
30 miles each way
Step-by-step explanation:
Answer: See step by step
Step-by-step explanation:
Since GJ is the perpendicular bisector of HK it bisects HK and make J the midpoint of HK. Since J is the midpoint we can construct a congruence statement of KJ≅JH. Then we know in the diagram Angle MJK= 90°, becuase it form a ⊥ line so it is 90° that also means MHJ forms a 90 ° angles becuase they also form a ⊥ line. So that means KJM≅HJM because of transitive property(a=b, b=c, then a=c). Both triangles also include side MJ, so using the reflexitive property( a=a),They are congruent. Since we proved they have a two congruent sides, with a included angle in between them we can use the SAS theorem (Side-Angle-Side) to prove they are congruent. So ΔKMJ≅ΔHMJ Then KM=HM by CPCTC.
Answer:

Step-by-step explanation:
Given:


As seen from the triangle, the triangle is a right angled triangle. Two sides of the triangle are given and we are asked to find the third side.
'x' is the hypotenuse as this side is opposite side to the right angled.
'y' and 'z' are the two legs of the triangle.
Now, using pythagoras theorem,

Therefore, the measure of the side 'z' is
.
Hence, the third option is correct.