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Aleksandr [31]
3 years ago
12

Bob drove from home to work at 75 mph.After work the traffic was heavier,and he drove home at 40 mph.His driving time to and fro

m work was 1 hour and 9 minutes.How far does he live from his job
Mathematics
1 answer:
Ilya [14]3 years ago
4 0

Answer:

Bob drove from home to work at 75 mph. After work the traffic was heavier, and he drove home at 40 mph. His driving time to and from work was 1 hour and 9 minutes. How far does he live from his job?

=================

Avg speed for the round trip = 2*75*40/(75+40) = 6000/115 = 1200/23 mi/hr

RT distance = 1200/23 * 69 minutes * 1 hr/60 mins =

= 60 miles

30 miles each way

Step-by-step explanation:

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marissa [1.9K]

Answer:

The value of Coefficients, Standard-error, t-Stat, P-value is given for sample of 10 trucks is given.

The correct regression line can be obtained by using the correct value of slope and intercept coefficient from the table.

Y

=

^

α

+

^

β

X

=>

1724.36

+

8.9

x

Hence, the correct option is option(b)

Step-by-step explanation:

5 0
3 years ago
A manufacturer of paper coffee cups would like to estimate the proportion of cups that are defective (tears, broken seems, etc.)
Maksim231197 [3]

Answer:

a

  The 95% confidence interval is  0.0503  <   p < 0.1297

b

The sample proportion is  \r p =  0.09

c

The critical value is  Z_{\frac{\alpha }{2} } =  1.96

d

 The standard error is  SE   =0.020

Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  200

     The number of defective is  k =  18

The null hypothesis is  H_o  :  p  =  0.08

The  alternative hypothesis is  H_a  :  p > 0.08

Generally the sample proportion is mathematically evaluated as

            \r p =  \frac{18}{200}

            \r p =  0.09

Given that the confidence level is  95% then the level  of significance is mathematically evaluated as

        \alpha  =  100 -  95

        \alpha  =  5\%

        \alpha  =  0.05

Next we obtain the critical value of  \frac{ \alpha }{2} from the normal distribution table, the value is  

        Z_{\frac{\alpha }{2} } =  1.96

Generally the standard of error is mathematically represented as

          SE   =  \sqrt{\frac{\r p (1 -  \r p)}{n} }

substituting values

         SE   =  \sqrt{\frac{0.09  (1 -  0.09)}{200} }

        SE   =0.020

The  margin of error is  

       E =  Z_{\frac{ \alpha }{2} }  * SE

=>    E =  1.96  *  0.020

=>   E =  0.0397

The  95% confidence interval is mathematically represented as

     \r p  -  E  <  \mu <  p <  \r p  + E

=>   0.09 - 0.0397  <  \mu <  p < 0.09 + 0.0397

=>  0.0503  <   p < 0.1297

7 0
3 years ago
For a certain casino slot machine comma the odds in favor of a win are given as 7 to 93. Express the indicated degree of likelih
ruslelena [56]

Answer:

0.07

Step-by-step explanation:

it is given odds in favor of a win is 7 to 93

we have to find the degree of likelihood as a probability

total sample space =7+93=100

so the degree of likelihood as a probability = \frac{7}{100} =0.07

so we can conclude that the probability will be 0.07 which is very less so the chances of win in the casino is very less

3 0
3 years ago
Plz help me get the right answer ASAP please
Ierofanga [76]
<h2>Greetings!</h2><h3>When expanding brackets, you simply multiply whatever is inside the brackets by what is outside:</h3>

(7x * x) + (7x * 20)

<h3>Which would result in the answer being:</h3>

7x^{2} + 140x


<h2>Hope this helps!</h2>
5 0
3 years ago
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Airida [17]

Answer:

Oh this is easy it is 6 so yea I'm right

7 0
3 years ago
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