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Colt1911 [192]
3 years ago
8

A bat, flying at 7.00 m/s toward a wall, emits a chirp at 50.0 kHz. If the wall reflects this sound pulse, what is the frequency

of the echo received by the bat? (vsound = 340 m/s)
Physics
1 answer:
777dan777 [17]3 years ago
3 0

Answer:

Explanation:

Given

Velocity of bat v_o=7\ m/s

Frequency of sound f=50\ kHz

velocity of sound v=340\ m/s

using Doppler Effect apparent frequency is given by

f'=f\cdot \frac{v-v_o}{v+v_s}

where  

f'=apparent frequency  

v=velocity of sound in the given media

v_s=velocity of source

v_o=velocity of observer      

here velocity of source is zero

as source is travelling towards source thus

f'=50\cdot (\frac{340+7}{340})

f'=51.029\ Hz                            

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A 5.67-kg block of wood is attached to a spring with a spring constant of 150 N/m. The block is free to slide on a horizontal fr
nikklg [1K]

Answer:

v=0.94 m/s

Explanation:

Given that

M= 5.67 kg

k= 150 N/m

m=1 kg

μ = 0.45

The maximum acceleration of upper block can be μ g.

 a= μ g                          ( g = 10 m/s²)

The maximum acceleration of system will ω²X.

ω = natural frequency

X=maximum displacement

For top stop slipping

μ g  =ω²X

We know for spring mass system natural frequency given as

\omega=\sqrt{\dfrac{k}{M+m}}

By putting the values

\omega=\sqrt{\dfrac{150}{5.67+1}}

ω = 4.47 rad/s

μ g  =ω²X

By putting the values

0.45 x 10 = 4.47² X

X = 0.2 m

From energy conservation

\dfrac{1}{2}kX^2=\dfrac{1}{2}(m+M)v^2

kX^2=(m+M)v^2

150 x 0.2²=6.67 v²

v=0.94 m/s

This is the maximum speed of system.

7 0
3 years ago
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What is physics? Why is it important in our life​
-Dominant- [34]

Answer:

It helps us to know or be aware of some things that happen regular and teaches us about laws that guide us

8 0
4 years ago
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To what extent are disorders the product of a particular environment, and to what extent
mixas84 [53]
Sorry don’t know hope you gave the answer to your questions
8 0
3 years ago
5)
Zina [86]

Answer:

The current through the wire is equal to 0.8 A.

Explanation:

Given that,

The length of a copper wire = 2 m

Potential difference = 24 mV

The current through the wire is 0.40 A.

The new potential difference is 48 mV.

We need to find the current through the wire.

As the potential difference is doubled for second wire. So the new current will be :

I' = 2I

= 2 × 0.4

= 0.80 A

So, the current through the wire is equal to 0.8 A.

5 0
3 years ago
Find the momentum (in kg.m/s) of a helium nucleus having a mass of 6.68 x 10^-27 kg that is moving at 0.386c.
igomit [66]

Answer:

7.73544\times 10^{-21}kgm/sec

Explanation:

We have given mass of helium nucleus m=6.68\times 10^{-27}kg

Velocity of helium nucleus v=0.386c=0.386\times 3\times 10^{8}m/sec=1.158\times 10^{8}m/sec

Momentum of the helium nucleus is given by P=mv where m is mass and v is velocity

So P=mv=6.68\times 10^{-27}\times 1.158\times 10^{8}=7.73544\times 10^{-21}kgm/sec

6 0
3 years ago
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