An 80-kg bungee jumper jumps off a bridge. Rubber bungee cords act as a large spring attaching the jumper to the bridge. A bear
1 answer:
Answer:
The force is
Explanation:
From the question we are told that
The mass of the bungee jumper is m = 80 kg
The spring constant is
The extension of the rubber bungee cords is x = 50 m
Generally the weight of the jumper is
=>
=> tex]W = 784 \ N [/tex]
Generally the returning force of the rubber bungee cords is mathematically represented as
=>
=>
The force to be applied by the bear is
=>
=>
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The magnetic force experienced by a charged particle moving at right angle in a magnetic field is given by:
where
q is the charge
v is the speed of the particle
B is the intensity of the magnetic field
In our problem, q=0.030 C, v=620 m/s and F=1.5 N, therefore if we re-arrange the equation and we plug these data into it, we find the intensity of the magnetic field:
where
q is the charge
v is the speed of the particle
B is the intensity of the magnetic field
In our problem, q=0.030 C, v=620 m/s and F=1.5 N, therefore if we re-arrange the equation and we plug these data into it, we find the intensity of the magnetic field:
Answer:
v = 0.823 m/s
Explanation:
A man walks south at a speed of 2.00 m/s for 60.0 minutes.
The distance covered in South = 60 × 60 × 2 = 7200 m
He then turns around and walks north a distance 3000 m in 25.0 minutes.
As they moved in opposite direction, net displacement will be : 7200 - 3000 = 4200 m
Average velocity of the man = net displacement/time
So, the average velocity of the man is 0.823 m/s.