Question

Find the momentum (in kg.m/s) of a helium nucleus having a mass of 6.68 x 10^-27 kg that is moving at 0.386c.

Answer 1

Answer:

$7.73544\times 10^{-21}kgm/sec$

Explanation:

We have given mass of helium nucleus $m=6.68\times 10^{-27}kg$

Velocity of helium nucleus $v=0.386c=0.386\times 3\times 10^{8}m/sec=1.158\times 10^{8}m/sec$

Momentum of the helium nucleus is given by $P=mv$ where m is mass and v is velocity

So $P=mv=6.68\times 10^{-27}\times 1.158\times 10^{8}=7.73544\times 10^{-21}kgm/sec$