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3 years ago

10

Radon is a radioactive gas found below ground. If a sample of radon occupies 29 mL at 25 oC, what volume will it occupy at 500 K

? Assume constant pressure.

1 answer:

Valentin [98]3 years ago

8 0

Answer:

48.63 mL

Explanation:

Using Charles's law

$\frac {V_1}{T_1}=\frac {V_2}{T_2}$

Given ,

V₁ = 29 mL

V₂ = ?

T₁ = 25 °C

T₂ = 500 K

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (25 + 273.15) K = 298.15 K

Using above equation as:

$\frac{29\ mL}{298.15\ K
}=\frac{V_2}{500\ K}$

$V_2=\frac{29\cdot \:500}{298.15}\ mL$

<u>New volume = 48.63 mL</u>

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