Two planes left an airport at noon. One flew east at a certain speed and the other flew west at twice the speed. The planes were
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Answer:
BE = 22.4 cm
Step-by-step explanation:
Δ CAB and Δ CDE are similar , then ratios of corresponding sides are equal, that is
=
, substitute values
=
( cross- multiply )
8 CE = 128 ( divide both sides by 8 )
CE = 16 cm
Then
BE = BC + CE = 6.4 + 16 = 22.4 cm
To find the angle of vertex E,we need to first find the sum of interior polygons to determine x:
In this case,the equation would be:
(7-2)×180°
=5×180°
=900°
We can then find the value of x:
(4)6x+(2)2x+8x=900°
24x+4x+8x=900°
36x=900°
x=25°
The interior angle of vertex E:
6x=6(25)=150°
Therefore,the interior angle of vertex E is 150°.
Hope it helps!
In this case,the equation would be:
(7-2)×180°
=5×180°
=900°
We can then find the value of x:
(4)6x+(2)2x+8x=900°
24x+4x+8x=900°
36x=900°
x=25°
The interior angle of vertex E:
6x=6(25)=150°
Therefore,the interior angle of vertex E is 150°.
Hope it helps!