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3 years ago

Kathleen correctly determines four arithmetic means between −7 and 14. What values does Kathleen determine?

Mathematics

1 answer:

Annette [7]3 years ago

5 0

Answer:

Kathleen determines the four arithmetic means to be −2.8 , 1.4, 5.6, and 9.8.

Step-by-step explanation:

The overall interval is 14 -(-7) = 21 units in length. The four equally-spaced "means" divide the interval into 5 equal parts, each one of which is ...

21/5 = 4.2

The four means are ...

-7 +4.2 = -2.8

-2.8 +4.2 = 1.4

1.4 +4.2 = 5.6

5.6 +4.2 = 9.8

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HW 7.4/7.5 help mhhhh

Hatshy [7]

Answer:

1. LI=18

2. x=10

3. Yes (Y)

4. Yes (Y)

5. x=15

6. x=18

7. x=8

8. x=6

y=6.5

Step-by-step explanation:

1. LI/JL=KH/JK

Replacing the given values:

LI/6=21/7

Dividing on the right side of the equation:

LI/6=3

Solving for LI: Multiplying both sides of the equation by 6:

6(LI/6)=6(3)

LI=18

2.TV/VS=RU/US

Replacing the given values:

x/17.5=8/14

Simplifying the fraction on the right side of the equation: Dividing numerator and denominator by 2:

x/17.5=(8/2) / (14/2)

x/17.5=4/7

Solving for x: Multiplying both sides of the equation by 17.5:

17.5(x/17.5)=17.5(4/7)=(17.5/1)(4/7)

Multiplying:

x=(17.5 x 4) / (1 x 7)

x=70/7

Dividing:

x=10

3. BC is parallel to DE if AD/DB is equal to AE/EC:

AD/DB=15/12=(15/3) / (12/3)→AD/DB=5/4

AE/EC=10/8=(10/2) / (8/2)→AE/EC=5/4

Like AD/DB=5/4=AE/EC → BC is parallel to DE

4. BC is parallel to DE if AD/DB is equal to AE/EC:

AD/DB= 2DB / DB→AD/DB=2

AE/EC=30 / (AC-AE)=30 / (45-30)=30/15→AE/EC=2

Like AD/DB=2=AE/EC → BC is parallel to DE

5. If JH is a midsegment of triangle KLM:

x=(1/2)(30)

x=15

6. If JH is a midsegment of triangle KLM:

x=2(9)

x=18

7. If JH is a midsegment of triangle KLM: x=8

8. 2x+1=x+7

Solving for x. Grouping the x's on the left side of the equation: Subtracting x both sides of the equation:

2x+1-x=x+7-x

Subtracting:

x+1=7

Subtracting 1 both sides of the equation:

x+1-1=7-1

Subtracting:

x=6

2x+1=2(6)+1=12+1→2x+1=13

x+7=6+7→x+7=13

(3y-8)/(y+5)=(2x+1)/(x+7)

(3y-8)/(y+5)=13/13

(3y-8)/(y+5)=1

3y-8=y+5

Solving for y. Grouping the y's on the left side of the equation: Subtracting y both sides of the equation:

3y-8-y=y+5-y

Subtracting:

2y-8=5

Adding 8 both sides of the equation:

2y-8+8=5+8

Subtracting:

2y=13

Dividing both sides of the equation by 2:

2y/2=13/2

Dividing:

y=6.5

3 0

3 years ago

Find an explicit rule for the nth term of the sequence.

Sphinxa [80]

Step-by-step explanation:

in a geometric sequence there is a constant factor x that is multiplied with every previous term to create the next one.

a2 = 20

a5 = 1280 = a2×x×x×x = a2×x³ = 20x³

64 = x³

x = 4

=> a1 = 5

therefore

an = an-1×4 =

$a1 \times {4}^{n - 1}$

n > 1

7 0

2 years ago

A 50% DISCOUNT IF THE SWAETSHIRT COST $64.75, HOW MUCH DID ADAM PAY ROUNDED TO THE NEASRT HUNDERTHS

Yakvenalex [24]

Answer: $32.38

Explanation:

64.75 = 100%

So that mean 50% would be half of 64.75

64.75 ÷ 2 = 32.375

8 0

2 years ago

Subtract 1/6a+3 from 1/3a−5<br> PLZ HELP ASAP

lukranit [14]

Answer:

1/3a - 5 - (1/6a + 3) =

1/3a - 5 - 1/6a - 3 =

1/3a - 1/6a - 5 - 3 =

2/6a - 1/6a - 8 =

1/6a - 8 <===

Step-by-step explanation:

5 0

3 years ago

If the average of x and y is 11 and the average of x, and y z is 5 what is the value of z

qwelly [4]

If the average of x and y is 11 and the average of x, y and z is 5, then the value of z is -7

Given,

The average of x and y = 11

We know average = Sum of the terms / Number of terms

Then, the equation will become

$\frac{x+y}{2}=11$
x+y =11×2

x+y =22

Average of x, y and z = 5

$\frac{x+y+z}{3}=5$

x+y+z = 5×3

x+y+z =15

Substitute the value of x+y

22+z=15

z =15-22

x = -7

Hence, If the average of x and y is 11 and the average of x, y and z is 5, then the value of z is -7

Learn more about average here

brainly.com/question/12984400

#SPJ4

6 0

1 year ago