All categories

3 years ago

Kathleen correctly determines four arithmetic means between −7 and 14. What values does Kathleen determine?

Mathematics

1 answer:

Annette [7]3 years ago

5 0

Answer:

Kathleen determines the four arithmetic means to be −2.8 , 1.4, 5.6, and 9.8.

Step-by-step explanation:

The overall interval is 14 -(-7) = 21 units in length. The four equally-spaced "means" divide the interval into 5 equal parts, each one of which is ...

21/5 = 4.2

The four means are ...

-7 +4.2 = -2.8

-2.8 +4.2 = 1.4

1.4 +4.2 = 5.6

5.6 +4.2 = 9.8

You might be interested in

The capacity of surfing is 0.08 liters.convert this to millimeters.

Fynjy0 [20]

80 Liters
(hope this helps)

7 0

4 years ago

<img src="https://tex.z-dn.net/?f=Determine%20the%20unknown%20quantity.%20Show%20your%20work.8%201%2F2%20over%203%202%2F3%20%3D%

san4es73 [151]

um approximatly 0.34519202904

5 0

2 years ago

Read 2 more answers

You have a box with dimensions 2 ft. x 4 ft. x 3 ft. a. If you want to wrap the box, what is the minimum amount of wrapping pape

shusha [124]

Answer: A) 52 ft B) $134.68

Step-by-step explanation:

First find the surface area by multiplying the dimensions together.

2 x 4 = 8

2 x 3 = 6

4 x 3 = 12

Then add them up and multiply by two because there are two of each side.

26 x 2 = 52

To find the cost, multiply 52 by $2.59 to get the price.

52 x $2.59 = $34.68

5 0

3 years ago

NEED HELP

Margaret [11]

Sorry I'm gonna take a guess.......... d?

4 0

3 years ago

See attachment the problem can be found in there

zloy xaker [14]

Answer:

$\frac{ - 2 {x}^{2} + 19x + 3 }{3 {x} (4x^{2} - 9 )}$

Step-by-step explanation:

$\frac{5}{6 {x}^{2} + 9x} + \frac{1}{2x - 3} - \frac{2}{3x} \\ \\ = \frac{5}{3x(2 {x} + 3)} + \frac{1}{2x - 3} - \frac{2}{3x} \\ \\ = \frac{5(2x - 3) + 1 \times 3x(2x + 3)}{3x(2 {x} + 3)(2x - 3)} - \frac{2}{3x} \\ \\ = \frac{10x - 15 + 6 {x}^{2} + 9x}{3x((2 {x} ) ^{2} - {3}^{2} )} - \frac{2}{3x} \\ \\ = \frac{6 {x}^{2} + 19x - 15}{3x(4x^{2} - 9 )} - \frac{2}{3x} \\ \\ = \frac{3x(6 {x}^{2} + 19x - 15) - 2 \times 3x(4x^{2} - 9 )}{3x(4x^{2} - 9 ) \times 3x} \\ \\ = \frac{18{x}^{3} + 57 {x}^{2} - 45x - 24x^{3} + 54x }{3x(4x^{2} - 9 ) \times 3x} \\ \\ = \frac{ - 6 {x}^{3} + 57 {x}^{2} + 9x }{9 {x}^{2} (4x^{2} - 9 )} \\ \\ = \frac{ 3x(- 2 {x}^{2} + 19x + 3) }{9 {x}^{2} (4x^{2} - 9 )} \\ \\ \huge \orange{ \boxed{= \frac{ - 2 {x}^{2} + 19x + 3 }{3 {x} (4x^{2} - 9 )} }}$

7 0

3 years ago