The firs term
A(1)=-6+(1-1)(6)
A(1)=-6+(0)(6)
A(1)=-6
The fourh term
A(n)=-6+(n-1)(6)
A(4)=-6+(4-1)(6)
A(4)=-6+(3)(6)
A(4)=-6+18
A(4)=12
The tenth term
A(10)=-6+(10-1)(6)
A(10)=-6+(9)(6)
A(10)=-6+54
A(10)=48
Answer:
D. -6,12,48
The answer is a since 150/6 is 25
Answer:
The given linear equation are
⇒9x+3y+12=0....eq1
⇒a1
=9,b1
=3,c1
=12
⇒18x+6y+24...eq2
⇒a2
=18,b2
=6,c2
=24
⇒a1/a2
=9/18 =1/2
⇒ b1/b2= 3/6 = 1/2
⇒ c1/c2= 12/24= 1/2
comparing
⇒ a1/a2,b1/b2,c1/c2
⇒ a1/a2=b1/b2=c1/c2
Hence, the line represented by eq1 and eq2 are coincidents
Step-by-step explanation:
Your answer is P= -8. Hope this helps.
Answer:
4
Step-by-step explanation:
f(p) = 3p-2
Let p=2
f(2) = 3*2-2
= 6-2
= 4
