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o-na [289]
3 years ago
9

Please answer this question now

Mathematics
2 answers:
SOVA2 [1]3 years ago
8 0

Answer:

<u>292.77</u>

Step-by-step explanation:

πr(r+\sqrt{h2+r2})

13 x 2 = 26

7 x 2 = 14

26 + 14 = 40

\sqrt{40} = 6.32

7 + 6.32 = 13.32

3.14 x 7 = 21.98

21.98 x 13.32 =

<u>292.77</u>

Ivan3 years ago
5 0

Answer:

Approximately 439.6 square millimeters.

Step-by-step explanation:

The formula for the surface area of a cone is the following:

A=\pi r^2+\pi r l

Where, <em>r </em>is the radius and <em>l</em> is the slant height.

The radius is 7 and the slant height is 13. We also use 3.14 for π Thus:

A=(3.14)(7)^2+(3.14)(7)(13)\\\text{Use a Calculator}\\A\approx 439.6

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Answer:

5 2/6

Step-by-step explanation:

you have to mutiply

3 0
3 years ago
Answer this 2(3^2 + 4^2) = ?
Vikentia [17]

Answer:

50

Step-by-step explanation:

2(3^2+4^2)=

3^2/(3x3) = 9

4^2/(4x4) = 16

9+16=25        

so.... rewritten it is

2(25)= or 2 x 25= 50

6 0
3 years ago
Really need help with this .
lions [1.4K]

Answer:

Step-by-step explanation:

The attached photo shows the diagram of quadrilateral QRST with more illustrations.

Line RT divides the quadrilateral into 2 congruent triangles QRT and SRT. The sum of the angles in each triangle is 180 degrees(98 + 50 + 32)

The area of the quadrilateral = 2 × area of triangle QRT = 2 × area of triangle SRT

Using sine rule,

q/SinQ = t/SinT = r/SinR

24/sin98 = QT/sin50

QT = r = sin50 × 24.24 = 18.57

Also

24/sin98 = QR/sin32

QR = t = sin32 × 24.24 = 12.84

Let us find area of triangle QRT

Area of a triangle

= 1/2 abSinC = 1/2 rtSinQ

Area of triangle QRT

= 1/2 × 18.57 × 12.84Sin98

= 118.06

Therefore, area of quadrilateral QRST = 2 × 118.06 = 236.12

6 0
3 years ago
Read 2 more answers
Which equation describes a parabola that opens left or right and whose vertex is at the point (h, v)?
nalin [4]
Vertex is at the point ( h , v ) 
The equation of a parabola is:
x = a ( y - v )² + h
Answer: B )
4 0
2 years ago
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If a polynomial function f(x) has roots 6 and square root of 5, what must also be a root of f(x)?
ivolga24 [154]

Answer:

-\sqrt{5}

Step-by-step explanation:

A root with square root or under root is only obtained when we take the square root of both sides. Remember that when we take a square root, there are two possible answers:

  • One answer with positive square root
  • One answer with negative square root

For example, for the equation:

x^{2}=3

If we take the square root of both sides, the answers will be:

x=\sqrt{3} \text{ or } x= -\sqrt{3}

Only getting one solution with square root is not possible. Solutions with square root always occur in pairs.

For given case, the roots are 6 and \sqrt{5}. Therefore, the 3rd root of the polynomial function f(x) had to be -\sqrt{5}

It seems you made error while writing option B, it should be - square root of 5.

4 0
3 years ago
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