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fomenos
3 years ago
15

What is the slope of the tangent line through (0,-3) and (x,y) for y = 3x2 - 3 and x=1?

Mathematics
1 answer:
julsineya [31]3 years ago
4 0
First you must derive the equation to find the slope:
 y = 3x ^ 2 - 3
 y '= 6x
 Then, for x = 1 we have the slope is:
 y '(1) = 6 (1) = 6
 Then the equation of the line with slope equal to 6 and passing through point (0, -3) is:
 y = 6x - 3
 The slope is m = 6
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3 years ago
Find the equation of the line shown.
Luda [366]

Answer:

y = -x + 9

Step-by-step explanation:

✔️Find the slope using (9, 0) and (7, 2):

slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{2 - 0}{7 - 9} = \frac{2}{-2} = -1

Slope (m) = -1

✔️Find the y-intercept (b):

The line intercepts the y-axis when y = 9. Therefore, y-intercept (b) = 9

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Thus,

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5 0
3 years ago
Trains Two trains, Train A and Train B. weigh a total of 196 tons. Train A is heavier than Train B. The
aleksklad [387]

Answer:

Train A = 128

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Step-by-step explanation:

We can set up a system of equations for this problem

Let A = # of tons of Train A

Let B = # of tons of Train B

A + B = 196

A = B + 60

Now, we plug in A for the first equation, using substitution

(B+60) + B = 196

2B + 60 = 196

Subtract 60 from both sides

2B = 136

Divide both sides by 2

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Plug in 68 for B in the 2nd equation

A = 68 + 60

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Checking work: 128 + 68 = 196 :D hope this helped

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Step-by-step explanation:

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5 0
2 years ago
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