3 years ago

What is the slope of the tangent line through (0,-3) and (x,y) for y = 3x2 - 3 and x=1?

1 answer:

4 0

First you must derive the equation to find the slope:
y = 3x ^ 2 - 3
y '= 6x
Then, for x = 1 we have the slope is:
y '(1) = 6 (1) = 6
Then the equation of the line with slope equal to 6 and passing through point (0, -3) is:
y = 6x - 3
The slope is m = 6

You might be interested in

Can someone please help me out? This is literally torture.

kupik [55]

3. There are 4 friends. A quarter of 4 is 25%. You can prove this by multipling 25% by 4 of the friends to get 100%. There is a 25% chance of Jonathon arriving first and a 25% chance that Michel will arrive second.

5 0

3 years ago

Read 2 more answers

Given z1 and z2, what is the midpoint?<br><br> z1=5-7i and z2=-9+3i.

sveta [45]

Answer:

$7-2i$

Step-by-step explanation:

As you're used to do in the real plane, midpoint is the average of Real and Imaginary part. So $\frac{5+9}2 +i \frac{-7+3}2 = \frac{14}2+i\frac{-4}2 = 7-2i$

7 0

2 years ago

Please solve this help

JulsSmile [24]

Answer:

the answer is the 3rd option. Hope it helped :)

8 0

3 years ago

Sarah and amanda each have 2 bags with 4 marbles in each .how many marbles do they have altogether?

djyliett [7]

Alltogether they have 16 marbles

3 0

3 years ago

Read 2 more answers

I need help asap plot it or locate it!

natulia [17]

You can plot this by turning the fraction into a decimal. -1&1/3rds is -1.333... and 1/6ths is about .16, so then you can find these points on the number line. Also, the number line has 6 points equal one, so the points by those.

3 0

3 years ago

Read 2 more answers