Answer:
The possible values of the number of dollars in the original pile of money is ≥ $200 but < $350
Step-by-step explanation:
Here we have, pile of money ≥ $200
Amount in put the left pocket = $50
Fraction given away = 2/3 of rest of pile ≥ 2/3×150 ≥ $100
Amount put in right pocket = ≥ $150 - $100 ≥ $50
Total amount remaining with Jeri = $50 +≥ $50 ≥ $100
Also original pile - $200 < $100
Therefore where maximum amount given away to have more money = $200 we have
2/3× (original pile - 50) = $200
Maximum amount for original pile = $350
Therefore the possible values of the number of dollars in the original pile of money is ≥ $200 but < $350.
Well what exactly do you need help with?
1L=1000mL
2800 mL=2.8L
If she needs 3.5 L, she currently has 2.8L,
so 3.5-2.8=0.7 L more or .7x1000=700 more mL
Answer:
97.5
Step-by-step explanation:
Cross multiply
2 * x = 2x
15 * 13 = 195
2x = 195
2x/2 = 195/2
x = 97.5
[RevyBreeze]
This is how to solve this
