Need help with da mafs Pls get it right lol I already have an 80 on this assignment

Liam's breakfast was an egg and cheese biscuit with a carton of milk. He spent a total of $5.65. Finn spent $7.65 on an egg and

ruslelena [56]

Answer:

An egg and cheese biscuit was $3.65.

Step-by-step explanation:

Liam's breakfast was:

$P = E + C + M$

Where:

P: total price

E: egg

C: cheese biscuit

M: carton of milk

$P = E + C + M$

$5.65 = E + C + M$ (1)

Now, Finn's breakfast was:

$P = E + C + 2*M$

$7.65 = E + C + 2*M$ (2)

By subtracting equation (2) from (1) we have:

$7.65 - 5.65 = 2M - M$

$M = 2$

Hence, the price of a carton of milk is $2, so by entering this value into equation (1) we can find the price of an egg and cheese biscuit:

$5.65 = E + C + M$

$5.65 - 2 = E + C$

$E + C = 3.65$

Therefore, an egg and cheese biscuit was $3.65.

I hope it helps you!

7 0

3 years ago

Faced with rising fax costs, a firm issued a guideline that transmissions of 10 pages or more should be sent by 2-day mail inste

Vladimir [108]

Answer:

The value of t test statistics is 5.9028.

We conclude that the true mean is greater than 10 at the .01 level of significance.

Step-by-step explanation:

We are given that a firm issued a guideline that transmissions of 10 pages or more should be sent by 2-day mail instead.

The firm examined 35 randomly chosen fax transmissions during the next year, yielding a sample mean of 14.44 with a standard deviation of 4.45 pages.

Let $\mu$ = true mean transmission of pages.

So, Null Hypothesis, $H_0$ : $\mu$ $\leq$ 10 pages {means that the true mean is smaller than or equal to 10}

Alternate Hypothesis, $H_A$ : $\mu$ > 10 pages {means that the true mean is greater than 10}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = 14.44 pages

s = sample standard deviation = 4.45 pages

n = sample of fax transmissions = 35

So, test statistics = $\frac{14.44-10}{\frac{4.45}{\sqrt{35} } }$ ~ $t_3_4$

= 5.9028

(a) The value of t test statistics is 5.9028.

Now, at 0.01 significance level the z table gives critical values of 2.441 at 34 degree of freedom for right-tailed test.

Since our test statistics is more than the critical values of z as 5.9028 > 2.441, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the true mean is greater than 10.

(b) Now, P-value of the test statistics is given by the following formula;

P-value = P( $t_3_4$ > 5.9028) = Less than 0.05% {using t table)

7 0

3 years ago

Find -3/7 divided by -15/1

posledela

Answer:

1/35

Step-by-step explanation:

-3/7 / -15/1 =

3/7 * 1/15 =

3 / 105 =

1/35

6 0

3 years ago

Find the centroid for an area defined by the equations y = x² + 3 and y = - (x – 2)² + 7

sergeinik [125]

First we need to find where the 2 graphs intercept.

x^2 + 3 = - (x^2 - 4x + 4) + 7
x^2 + 3 = -x^2 + 4x + 3
2x^2 - 4x = 0
2x(x - 2)

x = 0 , 2. are x coordinates of the 2 intercepts.

6 0

3 years ago

Simplify the expression 3x(x – 12x) + 3x2 – 2(x – 2)2. Which statements are true about the process and simplified product? Selec

Ann [662]

To solve the problem we must know about the Like terms and expressions.

<h3>What is an Expression?</h3>

In mathematics, an expression is a set of numbers, variables, and mathematical operations formed according to rules.

Given ;

$3x(x - 12x) + 3x^2 - 2(x - 2)^2$

To solve the algebraic expression,

$3x(x - 12x) + 3x^2 - 2(x - 2)^2\\\\3x(x - 12x) + 3x^2 - 2(x^2 - 4x + 4)\\\\3x(x - 12x) + 3x^2 - 2x^2 + 8x - 8\\\\3x^2 - 36x^2 + 3x^2 - 2x^2 + 8x - 8\\\\-33x^2 + x^2 + 8x - 8\\\\\\-32x^2 + 8x - 8\\$

To solve the problem we must know about the Like terms and expressions.

Learn more about Expression:

brainly.com/question/13947055

#SPJ1

7 0

2 years ago