Answer:
(a) moment generating function for X is 
(b) 
Step-by step explanation:
Given X represents the number on die.
The possible outcomes of X are 1, 2, 3, 4, 5, 6.
For a fair die, 
(a) Moment generating function can be written as 
.
(b) Now, find 
using moment generating function
Hence, (a) moment generating function for X is 
.
(b)
9514 1404 393
Answer:
64k^6 -64k^5 +(80/3)k^4 -(160/27)k^3 +(20/27)k^2 -(4/81)k +1/729
Step-by-step explanation:
The row of Pascal's triangle we need for a 6th power expansion is ...
1, 6, 15, 20, 15, 6, 1
These are the coefficients of the products (a^(n-k))(b^k) in the expansion of (a+b)^n as k ranges from 0 to n.
Your expansion is ...
1(2k)^6(-1/3)^0 +6(2k)^5(-1/3)^1 +15(2k)^4(-1/3)^2 +20(2k)^3(-1/3)^3 +...
15(2k)^2(-1/3)^4 +6(2k)^1(-1/3)^5 +1(2k)^0(-1/3)^6
= 64k^6 -64k^5 +(80/3)k^4 -(160/27)k^3 +(20/27)k^2 -(4/81)k +1/729
Let's rewrite the binomial as:
Using the binomial expansion, we get:
For the 15th term, we want the term where r is equal to 14, because of the fact that the first term starts when r = 0. Thus, for the 15th term, we need to include the 0th or the first term of the binomial expansion.
Thus, the fifteenth term is:
A. is your answer
Hope this helps! :)
The average is 0.9
-2.5 + 5.2 + 1.7 + (-0.8) = 3.6
3.6 / 4 = 0.9
