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sammy [17]
3 years ago
11

How would you solve? How do you figure out how to solve and what are helpful tips for future problems ?

Mathematics
1 answer:
Tresset [83]3 years ago
4 0
Since each odd (or even) is two greater than the previous number, two consecutive such numbers are n and n+2.

The we are told that the sum of two such number is 100, so we can say:

n+n+2=100  combining like terms on the left side you get:

2n+2=100


....

to solve, if you were interested...subtract 2 from both sides

2n=98  divide both sides by 2

n=49

So the two odd numbers are 49 and 51

You might be interested in
Rectangle A measures 10 inches by 8 inches. Rectangle B is an enlarged copy of Rectangle A. Select all of the measurement pairs
Fudgin [204]

Answer:

See Explanation

Step-by-step explanation:

Given

Rectangle A:

Length: 10\ in

Width: 8\ in

Required

Determine the possible dimensions of Rectangle B

<em>The question has missing options; however, the question can still be solved.</em>

<em></em>

Rectangle B being an enlarged copy of A implies that the dimension of A A is enlarged in equal proportion to form B

Take for instance, the measurements of Rectangle B are

Length: 15 in

Width: 12 in

Divide the corresponding lengths of B by A to get the enlargement ratio

Ratio = \frac{B}{A}

For length:

Ratio = \frac{15}{10}

Ratio = 1.5

For width

Ratio = \frac{12}{8}

Ratio = 1.5

Notice that both ratios are the same.

For this measurement of B, we can conclude that B is an enlargement of A

Assume another measurements for B

Length: 20\ in

Width: 10\ in

Calculate Ratios

Ratio = \frac{B}{A}

For length:

Ratio = \frac{20}{10}

Ratio = 2

For width

Ratio = \frac{10}{8}

Ratio = 1.25

Notice that, both ratios are not equal.

For this measurement of B, we can conclude that B is not an enlargement of A

<em>Conclusively, all you have to do is: determine the ratios of the dimensions of B to A, if the result are equal then B is an enlarged copy of A; if otherwise, then B is not an enlarged copy</em>

5 0
3 years ago
Jillian measured the distance around a small fish pond as 27 yards. Which would be a good estimate for the distance across the p
ankoles [38]
27 (circumference) ➗ 3.14 (pi) = 8.59 (diameter)

Distance across (diameter) would be closest to 9.
4 0
3 years ago
Someone ask me to solve this.
Semenov [28]
X=2h, y=3k

Substitute these values into equations.

y+2x = 4 ------> 3k+2*2h=4 ----->  3k +4h =4

2/y - 3/2x = 1-----> 2/3k -3/(2*2h) = 1 ------> 2/3k - 3/4h =1

We have a system of equations now.

 3k +4h =4          ------> 3k = 4-4h ( Substitute 3k in the 2nd equation.)
2/3k - 3/4h =1

2/(4-4h) -3/4h = 1
2/(2(2-2h)) - 3/4h = 1
1/(2-2h) -3/4h - 1=0

4h/4h(2-2h) -3(2-2h)/4h(2-2h) - 4h(2-2h)/4h(2-2h) =0

(4h- 3(2-2h) - 4h(2-2h))/4h(2-2h) = 0
Numerator should be = 0
4h- 3(2-2h) - 4h(2-2h)=0

Denominator cannot be = 0
4h(2-2h)≠0

Solve equation for numerator=0
4h- 3(2-2h) - 4h(2-2h)=0
4h - 6+6h-8h+8h² =0
8h² +2h -6=0
4h² + h-3 =0
(4h-3)(h+1)=0
4h-3=0, h+1=0
h=3/4  or h=-1

Check which
4h(2-2h)≠0
1) h= 3/4  , 4*3/4(2-2*3/4)=3*(2-6)= -12 ≠0, so we can use h= 3/4
2)h=-1, 4(-1)(2-2*(-1)) =-4*4=-16 ≠0, so we can use h= -1, also.

h=3/4, then  3k = 4-4*3/4 =4 - 3=1 , 3k =1, k=1/3
h=-1, then  3k = 4-4*(-1) =8 , 3k=8, k=8/3 

So,
if h=3/4, then  k=1/3,
and if h=-1, then  k=8/3 .




6 0
2 years ago
Complete the sentence 0,5,1,6,2,7 _,_
Scorpion4ik [409]
3,8
That’s the answer Hope this helped
7 0
2 years ago
What is the outlier for the data set?
Gnesinka [82]
The outlier is 9

Explanation

An outlier is a number that is at least 2 standard deviations away from the mean. For example, in the set, 1,1,1,1,1,1,1,7, “7 “would be the outlier.
3 0
2 years ago
Read 2 more answers
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