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galben [10]
3 years ago
8

The formula for the surface area of a rectangular prism with a square base is SA=2s2+4shSA=2s2+4sh. What is the surface area of

this rectangular prism if s=3s=3 and h=5?
Mathematics
2 answers:
mafiozo [28]3 years ago
7 0

Answer:

The answer is 90 sq ft!

Have a great day!

Ivanshal [37]3 years ago
4 0
This is the concept of algebra, given that the formula for the surface area of the prism is modeled by the expression SA=2s²+4sh , the surface area of the prism when s=3 and h=5 will be found by substituting the values in our expression as follows;
SA=2(3)²+4×3×5
SA=2(9)+60
SA=18+60
SA=78 sq. units
The answer is 78 sq. units

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pashok25 [27]

Answer:

All real numbers greater than 0

Step-by-step explanation:

When you look at   y = log (2)  x

Base 2,   exponent y.

x =  2^y

x  can only be a positive number.

7 0
3 years ago
The boy the apartment building is filling a pool 30 ft long 20 feet wide and 5 feet deep it has been filled 4 ft deep how many m
inn [45]
Capacity of the pool = 30 x 20 x  5 = 3000 ft³

Amount of water already filled = 30 x 20 x 4 = 2400 ft²

Amount of water needed to full the pool = 3000 - 2400 = 600 ft²


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Answer: 600 ft² of water is needed to fill up the pool.
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4 0
3 years ago
Read 2 more answers
Hello people ~
Luden [163]

Cone details:

  • height: h cm
  • radius: r cm

Sphere details:

  • radius: 10 cm

================

From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.

<u>Using Pythagoras Theorem</u>

(a)

TO² + TU² = OU²

(h-10)² + r² = 10²                                   [insert values]

r² = 10² - (h-10)²                                     [change sides]

r² = 100 - (h² -20h + 100)                       [expand]

r² = 100 - h² + 20h -100                        [simplify]

r² = 20h - h²                                          [shown]

r = √20h - h²                                       ["r" in terms of "h"]

(b)

volume of cone = 1/3 * π * r² * h

===========================

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (\sqrt{20h - h^2})^2  \  ( h)

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (20h - h^2)  (h)

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (20 - h) (h) ( h)

\longrightarrow \sf V = \dfrac{1}{3} \pi h^2(20-h)

To find maximum/minimum, we have to find first derivative.

(c)

<u>First derivative</u>

\Longrightarrow \sf V' =\dfrac{d}{dx} ( \dfrac{1}{3} \pi h^2(20-h) )

<u>apply chain rule</u>

\sf \Longrightarrow V'=\dfrac{\pi \left(40h-3h^2\right)}{3}

<u>Equate the first derivative to zero, that is V'(x) = 0</u>

\Longrightarrow \sf \dfrac{\pi \left(40h-3h^2\right)}{3}=0

\Longrightarrow \sf 40h-3h^2=0

\Longrightarrow \sf h(40-3h)=0

\Longrightarrow \sf h=0, \ 40-3h=0

\Longrightarrow \sf  h=0,\:h=\dfrac{40}{3}<u />

<u>maximum volume:</u>                <u>when h = 40/3</u>

\sf \Longrightarrow max=  \dfrac{1}{3} \pi (\dfrac{40}{3} )^2(20-\dfrac{40}{3} )

\sf \Longrightarrow maximum= 1241.123 \ cm^3

<u>minimum volume:</u>                 <u>when h = 0</u>

\sf \Longrightarrow min=  \dfrac{1}{3} \pi (0)^2(20-0)

\sf \Longrightarrow minimum=0 \ cm^3

6 0
2 years ago
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Suppose sin(A) = 1/4. use the trig identity sin^2(A)+cos^2(A)=1 to find cos(A) in quadrant II. around to ten-thousandth.
larisa86 [58]

In quadrant II, \cos(A) will be negative. So

\sin^2(A) + \cos^2(A) = 1 \implies \cos(A) = -\sqrt{1 - \sin^2(A)} = -\dfrac{\sqrt{15}}4 \approx \boxed{-0.9682}

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2 years ago
Michael reads 12 pages of a book in 18 minutes, 8 pages in 12 minutes, and 20 pages in 30 minutes. I’d this a proportional relat
Alex73 [517]

Answer:

Y= 1.5x

Step-by-step explanation:

What you would do is divide all of the minutes by the amount of pages to find how long for each rate for one page. (ex. 18/12, Michael reads 1 page in 1.5 minutes. 12/8, Michael reads 1 page in 1.5 minutes. 30/20, Michael reads one page in 1.5 minutes) Therefore, yes it is proportional, and the equation is y=1.5x (there is no y intercept)

I hope this will help

4 0
3 years ago
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