Short Answers
P(Both) = 0.1792
Givens
The total number of roles = 100
Total number of heads = 56
Number of times rolled a four = 32 [check this for me].
Set up the probabilities.
P(H) = 56/100
P(4) = 32/100
P(H)*P(4) = P(Both)
Substitute and solve
P(Both) = 56/100 * 32/100 = 1792/10000
P(Both) = 112/625 because there are many cancellations. Or you could just express it as 0.1972
Answer:
Plz take full pick so discussing
These require you solve for y. Do that by subtracting the x-term, then dividing by the y-coefficient.
5. 3y = 7x -9
y = (7/3)x -3
6. 6y = -2x -3
y = (-2/6)x -3/6
y = (-1/3)x -1/2
7. 8y = 2x + 12
y = (1/4)x +3/2
102 grams would be remaining after a total of 3 half lifes occur in 105 days
20%
Because Suppose x% of 20 is 4
That is
x100×20=4
or
x5=4
—> =4×5=20
So 20% of 20 is 4

