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Vadim26 [7]
3 years ago
10

Why is the answer to this B?

Chemistry
1 answer:
attashe74 [19]3 years ago
3 0
Even if you know no chemistry at all, the diagram itself gives you a hint. If the answer is either A or D you have two answers that if you actually do this that are too close to call. Chromatography is not a very precise procedure. 

However you should not give that as your reason for answering. The answer is B because the ink that represents B is hardest to dislodge from the solvent. That's because likes dissolve best in likes. So the energy needed to climb that height is provided by the two traveling together. Two means solvent in ink.The other inks all break away much sooner because The solvent / ink complex cannot stay together and move at the same time.
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Need help please?!!!!!​
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(a) 33.6 L of oxygen would be produced.

(b) 106 grams of  Na_2CO_3 would be needed

<h3>Stoichiometric calculations</h3>

1 mole of gas = 22.4 L

(a) From the equation, 2 moles of KClO_3 produce 3 moles of O_2. 1 mole of  KClO_3 will, therefore, produce 1.5 moles of  O_2.

1.5 moles of oxygen = 22.4 x 1.5 = 33.6 L

(b) 22.4 L of CO_2 is produced at STP. This means that 1 mole of the gas is produced.

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Molar mass of  Na_2CO_3 = (23x2)+ (12)+(16x3) = 106 g/mol

Mass of 1 mole  Na_2CO_3 = 1 x 106 = 106 grams

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6 0
2 years ago
Find the empirical formula of the following compounds:<br> (c) A hydrocarbon with 79.9 mass % carbon
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In chemistry, the empirical formula of a chemical compound is the simplest whole number ratio of atoms present in a compound.

<h3>Describe the empirical formula.</h3>

The simplest whole number ratio of atoms in a compound is the empirical formula of a chemical compound in chemistry. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S2O2, are two straightforward examples of this idea.

The simplest whole number ratio of each type of atom in a compound is its empirical formula. It can be determined from data on the mass of each component in a compound or from the composition's proportion.

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