-11/12 - -5/12 as always please explain

2 answers:

4 0

Well for starters, to negatives next to eachother make a positive. So now we rewrite the problem, -11/12 + 5/12.

Since 11/12 is bigger than 5/12, we use the bigger number’s sign which is subtraction. So 11/12 - 5/12 = 6/12.

However, you want the answer to be in simplest form. You can break down 6/12 to a smaller fraction by dividing 6 into both numbers. 6 divides by 6 is 1. And 12 divided by 6 is 2.

So your final answer is 1/2. Also known as half. I hope this helped.

alekssr [168]3 years ago

3 0

-11/12 +5/12 = - 6/12= - 1/2

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Consider the following hypothesis test:

Gnom [1K]

Answer:

a. z=3.09. Yes, it can be concluded that the population mean is greater than 50.

b. z=1.24. No, it can not be concluded that the population mean is greater than 50.

c. z=2.22. Yes, it can be concluded that the population mean is greater than 50.

Step-by-step explanation:

We have a hypothesis test for the mean, with the hypothesis:

$H_0: \mu\leq50\\\\H_a:\mu> 50$

The sample size is n=55 and the population standard deviation is 6.

The significance level is 0.05.

We can calculate the standard error as:

$\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{55}}=0.809$

For a significance level of 0.05, the critical value for z is zc=1.644. If the test statistic is bigger than 1.644, the null hypothesis is rejected.

a. If the sample mean is M=52.5, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{52.5-50}{0.809}=\dfrac{2.5}{0.809}=3.09$

The null hypothesis is rejected, as z>zc and falls in the rejection region.

b. If the sample mean is M=51, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51-50}{0.809}=\dfrac{1}{0.809}=1.24$

The null hypothesis failed to be rejected, as z<zc and falls in the acceptance region.

c. If the sample mean is M=51.8, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51.8-50}{0.809}=\dfrac{1.8}{0.809}=2.22$

The null hypothesis is rejected, as z>zc and falls in the rejection region.

8 0

4 years ago

A projectile is shot into the air following the path,h(x) = - 5t2 + 20t + 3. At what time will it reach a maximum height? t = 1

kramer

Answer:

t = 2

Step-by-step explanation:

Notice that this expression for the projectile's path is that of a quadratic function with negative leading term. The graph of it therefore consists of a parabola with the branches pointing down (due to he negative leading coefficient). Therefore, the maximum of such parabola will reside at its vertex.

Recall that the formula for the position of the vertex in a general parabolic function of the form: $y(x)=ax^2+bx+c$ , is given by the expression: $x_{vertex}=-\frac{b}{2a}$