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11Alexandr11 [23.1K]
3 years ago
14

A swimming pool can be filled by either or both of two pipes of different diameters. it takes the smaller pipe twice the time th

at the larger pipe takes to fill the pool. if water flows through both pipes it take 213 hours to fill the pool. how long will it take the larger pipe to fill the pool? [hint: let x be the amount of the pool filled by the small pipe in one hour]
Mathematics
2 answers:
Radda [10]3 years ago
8 0
<h2>By large pipe only it will take 319.5 hours to fill the pool.     </h2>

Step-by-step explanation:

Let r₁ be the rate of filling of small pipe, r₂ be the rate of filling of large pipe  and V be the volume of swimming pool.

\texttt{Rate of small pipe},r_1=\frac{V}{t_1}\\\\\texttt{Rate of large pipe},r_2=\frac{V}{t_2}=\frac{V}{0.5t_1}=2r_1

If both pipes are combined it takes 213 hours, that is

              t=\frac{V}{r_1+r_2}\\\\213=\frac{V}{r_1+2r_1}\\\\V=639r_1

Now we need to find how much time it takes to fill the pool by large pipe,

That is

               t_2=\frac{V}{r_2}=\frac{639r_1}{2r_1}=319.5hours

By large pipe only it will take 319.5 hours to fill the pool.          

liraira [26]3 years ago
5 0
X+y= 213
X=2y

2y+ y=213,y=71
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The solution to –2(8x – 4) < 2x + 5 is x > 1/6

<h3>How to solve the inequality?</h3>

The expression is given as:

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