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2 years ago

1 point

Mathematics

1 answer:

Jet001 [13]2 years ago

6 0

Answer:

no solution

Step-by-step explanation:

Given

8(3x - 6) = 6(4x + 8) ← distribute both sides

24x - 48 = 24x + 48 ( add 48 to both sides )

24x = 24x + 96 ( subtract 24x from both sides )

0 = 96 ← not possible

This indicates the equation has no solution

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Solve the following system of equations using substitution.

stira [4]

It is A maybe use your calculator

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2x² +6 = 8x<br>what are the values of x here?

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X1 = 1
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Given three consecutive odd integers, what is the greatest number if triple of the sum of thrice the third one and twice the fir

Nostrana [21]

Let n be the smallest of these integers. The other two are then n + 2 and n + 4.

"triple of the sum of thrice the third one and twice the first one is equal to 291" is a long-winded way of saying

3 (3 (n + 4) + 2n) = 291

Solve for n :

3 (3n + 12 + 2n) + 291

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2 years ago

20 POINTS!!! PLZ ANSWER!! On the moon, the time, in seconds, it takes for an object to fall a distance, d, in feet, is given by

scoundrel [369]

Answer:

Part a) $f(2)=1.57\ sec$

It takes 1.57 seconds for an object to fall a distance of 2 feet

Part b) see the explanation

Part c) $2,165.43\ sec$

Step-by-step explanation:

Let

f(d) -----> the time in seconds it takes for an object to fall

d -----> distance in feet

we have

$f(d)=1.11\sqrt{d}$

Part a): Determine f(2) and explain what it represents

we know that

f(2) represent the time in seconds it takes for an object to fall a distance of 2 feet

For $d=2\ ft$

substitute in the function above and solve for f(2)

$f(2)=1.11\sqrt{2}$

$f(2)=1.57\ sec$

therefore

It takes 1.57 seconds for an object to fall a distance of 2 feet

Part b) The imbrium basin is the largest basin on the moon. A reasonable domain for the height above the lowest point in the basin is given by {d|0 ≤ d ≤ 3805774}

What does this tell you about the basin?

The height of the basin is greater than or equal to 0 ft and less than or equal to 3,805,774 ft

The maximum height of the basin is 3,805,774 ft

Part c) How long would it take a rock to drop from the rim to the bottom of the basin?

we know that

The distance from the rim to the bottom of the basin is equal to the maximum height of the basin

$d=3,805,774\ ft$

substitute the value of d in the function f(d)

$f(d)=1.11\sqrt{3,805,774}$

$f(d)=2,165.43\ sec$

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ruslelena [56]

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Step-by-step explanation:

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