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Oksi-84 [34.3K]
3 years ago
9

Find the difference (3-2x+2x^2)-(4x-5+3x^2)

Mathematics
1 answer:
attashe74 [19]3 years ago
3 0
5x^2+2x-2 if that is a help tell me what I have to find
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Please help me now plz I will mark you brainliest
PIT_PIT [208]

Answer:

On the circle

Step-by-step explanation:

Because all of the points on a circle are equidistant from the center, if a circle has a radius of 10 then all of the points are 10 units from the center. Using the Pythagorean Theorem, you know that the distance from (4,0) to (-2,8) is:

\sqrt{(4-(-2))^2+(8-0)^2}=\sqrt{6^2+8^2}=\sqrt{36+64}=\sqrt{100}=10, meaning that it is on the circle. Hope this helps!

7 0
3 years ago
Josh wrote 483 out of an expected 500 words from his essay. How would this ratio be
ehidna [41]

Answer:

0.966

Step-by-step explanation:

483:500 = 0.966

i hope this is right x

4 0
3 years ago
Read 2 more answers
Express each ratio as a fraction in lowest terms.
uranmaximum [27]
1. 5/6
2. 7/1
3. 1/7
Just write the first number as the numerator and the second one as a denominator then divide by their common factors
6 0
3 years ago
Write an inequality to represent each sentence. Use n for the variable.
Zepler [3.9K]

Answer:

17>n is the correct answer

7 0
2 years ago
Read 2 more answers
I don't know how to solve it.
Nataly [62]

Step-by-step explanation:

Take the first derivative

\frac{d}{dx} ( {x}^{3}  - 3x)

3 {x}^{2}  - 3

Set the derivative equal to 0.

3 {x}^{2}  - 3 = 0

3 {x}^{2}  = 3

{x}^{2}  = 1

x = 1

or

x =  - 1

For any number less than -1, the derivative function will have a Positve number thus a Positve slope for f(x).

For any number, between -1 and 1, the derivative slope will have a negative , thus a negative slope.

Since we are going to Positve to negative slope, we have a local max at x=-1

Plug in -1 for x into the original function

( - 1) {}^{3}  - 3(  - 1) = 2

So the local max is 2 and occurs at x=-1,

For any number greater than 1, we have a Positve number for the derivative function we have a Positve slope.

Since we are going to decreasing to increasing, we have minimum at x=1,

Plug in 1 for x into original function

{1}^{3}   - 3(1)

1 - 3 =  - 2

So the local min occurs at -2, at x=1

8 0
2 years ago
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