All categories

3 years ago

What is -536/4 as a mixed number?

Mathematics

1 answer:

solong [7]3 years ago

8 0

Answer:

-134

We cannot make a "mixed number" because -536-4 can already be divided...

As I like to keep my answers short, I hope you have a wonderful day!

You might be interested in

A rectangle with an area of 5/8 ft² is dilated by a factor of 8. What is the area of the dilated rectangle?

gulaghasi [49]

Answer:

40 ft²

Step-by-step explanation:

Let the length of the original rectangle be L and original Breadth be B

it is given that the original area is 5/8 ft²

i.e.

Original Length x Original Breadth = Original Area, or,

LB = 5/8 ft² ------------------(1)

Given that the dilation factor is 8,

Hence,

New Length = 8L and New Breadth = 8B

THerefore,

New Area = 8L x 8B

= 64 LB (from (1) above , we know that LB = 5/8 ft², substitute into expression)

= 64 (5/8)

= 40 ft²

4 0

3 years ago

a. Among a shipment of 5,000 tires, 1,000 are slightly blemished. If one purchases 10 of these tires, what is the probability th

hodyreva [135]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

3 or less than 3 tires among the 10 tires should be blemished.

There are some possibilities.

1000 tires are blemished, (5000 - 1000) = 4000 tires are not blemished.

From the 5000 tires, 10 tires can be chosen in $^{5000}C_{10}$ ways.

Possibility 1: <u>3 tires are blemished.</u>

Total 10 tires can be chosen with 3 blemished tires in $^{1000}C_3 \times {4000}C_7$ ways.

Possibility 2: <u>2 tires are blemished.</u>

Total 10 tires can be chosen with 2 blemished tires in $^{1000}C_2 \times ^{4000}C_8$ ways.

Possibility 3: <u>1 tires are blemished.</u>

Total 10 tires can be chosen with 1 blemished tires in $^{1000}C_1 \times^{4000}C_9$ ways.

Possibility 4: <u>No tires are blemished.</u>

Total 10 tires can be chosen with no blemished tires in $^{1000}C_0 \times^{4000}C_{10}$ ways.

Hence, the required probability is $\frac{^{1000}C_1 \times^{4000}C_9 + ^{1000}C_0 \times^{4000}C_{10} + ^{1000}C_2 \times^{4000}C_8 + ^{1000}C_3 \times^{4000}C_7}{^{5000}C_{10} }$ .

6 0

3 years ago

Given that A = (4,3,-4), B = (2,8,-5) and C = (-5,5,-8), find the vector from A to the midpoint of BC.

viktelen [127]

Mid-point of BC, M=(2+(-5),8+5,-5+(-8))/2=(-1.5, 6.5, -6.5)
Vector from A to M = M-A=<(-1.5,6.5,-6.5)-(4,3,-4)>=<-11/2,7/2,-5/2>

6 0

3 years ago

I need to know how its b quickly

goblinko [34]

It's B it even stars the correct answer for you

4 0

3 years ago

Please help! Rhombus LMNO is shown with its diagonals. The length of LN is 30 centimeters. What is the length of LP? A.) 14 B.)

gulaghasi [49]

Answer:

Step-by-step explanation:

Since the diagonals of a rhombus bisect each other, that means P is the midpoint of LN. Therefore, LP = 1/2 * LN = 1/2 * 30 = 15.

5 0

3 years ago