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3 years ago

10

A test has two parts, A and B, each containing 10 questions. A student needs to choose 8 questions from part A and 4 questions f

rom part B. In how many ways can he do that?

1 answer:

Tpy6a [65]3 years ago

3 0

Part A number of combinations of 8 from 10 = 10C8 = 10C2

= 10*9 / 2 = 45

Part B Number combinations = 10C4 = (10*9*8*7)/ (4*3*2) = 210

Total number of ways = 45 * 210 = 9450 (answer)

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