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patriot [66]
4 years ago
6

What is 8.478 in word form?

Mathematics
2 answers:
lys-0071 [83]4 years ago
8 0
Eight thousand four hundred and seventy eight
timama [110]4 years ago
7 0
Eight and four hundred seventy-eight thousandths
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What is the result of 8 divided by 3/8
igor_vitrenko [27]

Answer:

21 \frac{1}{3}

Step-by-step explanation:

Don't really know how to explain this over a computer, other than use a calculator.

Hope that this helps!

3 0
3 years ago
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You have 6 boys and 15 girls the is the ratio in the form of a fraction
bezimeni [28]

If you have six boys and fifteen girls, the ratio in the form of a fraction is 6/15.

8 0
4 years ago
A rectangle sandbox has a width of 5 feet. Tbe sandbox is 5 times as long as it is wide. What is the perimeter of the sandbox?
NikAS [45]
The perimeter of the sandbox is 60 ft.
5x5=25
Two sides = 25, so 25+25 = 50.
Two other sides = 5, so 5+5=10
50+10 = 60, and that is the correct answer.
If you would like any more assistance with this type of questions, let me know and I will be able to further assist you. Thank you!
6 0
4 years ago
What do you know to be true about the values of p and q?
gizmo_the_mogwai [7]

Answer:

p=q

Step-by-step explanation:

all angles together is 180. p=70 degrees and q = 70 degrees

5 0
3 years ago
Suppose you earn 3% on a $1,200 deposit for 5 years. Explain how the simple interest is affected if the rate is increased by 1%.
coldgirl [10]
\bf ~~~~~~ \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$1200\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
t=years\to &5
\end{cases}
\\\\\\
I=1200(0.03)(5)\implies \boxed{I=180}\\\\
-------------------------------

\bf ~~~~~~ \textit{Simple Interest Earned increased by 1\%}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$1200\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
t=years\to &5
\end{cases}
\\\\\\
I=1200(0.04)(5)\implies \boxed{I =240}\\\\
-------------------------------

\bf ~~~~~~ \textit{Simple Interest Earned increased by 1 year}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$1200\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
t=years\to &6
\end{cases}
\\\\\\
I=1200(0.03)(6)\implies \boxed{I =216}
8 0
4 years ago
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