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mars1129 [50]
3 years ago
10

Carlotta is constructing an equilateral triangle. She has already constructed the line segment and arc shown. What should Carlot

ta do for her next step?
Use the straightedge to draw a line that passes through point Q and intersects the arc.

Place the point of the compass on point Q and draw an arc that intersects the first arc, using the same width for the opening of the compass as the first arc.

Use the straightedge to draw a line that passes through point P and intersects the arc.

Place the point of the compass on point Q and draw an arc that intersects the first arc, using a width for the opening of the compass that is less than 1/2 PQ.

Mathematics
1 answer:
True [87]3 years ago
7 0
Given that <span>Carlotta is constructing an equilateral triangle. and that she has already constructed the line segment and arc shown.

What Carlotta should do for her next step is </span>"p<span>lace the point of the compass on point Q and draw an arc that intersects the first arc, using the same width for the opening of the compass as the first arc.</span>"
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que ecuación se podria usar para encontrar la circunferencia en pies de un circulo con un radio de 7 pies? ​
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Answer:

Tu respuesta

Step-by-step explanation:

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2 years ago
1. Try It # 1 A company sells doughnuts. They incur a fixed cost of $25,000 for rent, insurance, and other expenses. It costs $0
Y_Kistochka [10]

Answer:

The y-intercept is 25000 . The intercept is the fixed cost of the doughnut selling company.

Step-by-step explanation:

In the question, it is given that the fixed cost is $25000 and the expense to produce each doughnut is $0.25.

It is required to find and identify the y intercept.

To do so, use the equation derived in previous part of the exercise to interpret the slope. Compare the equation with standard equation of the line.

Step 1 of 1

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5 0
2 years ago
HELP ASAP WILL MARK BRAINLIEST
DochEvi [55]

Answer:

EF , HG , Parallel

Step-by-step explanation:

Here we are given a translated quadrilateral EFGH from Quadrilateral ABCD.

Also given that AB was parallel to DC.

Now we have to fill in the certain blanks.

Here EF is parallel to AB , As EFGH is a translated image of ABCD. And EF and AB are the corresponding sides.

Also HG is parallel to DC, EFGH is a translated image of ABCD.

Also we are given that AB is parallel to DC. Hence we have following results.

AB║DC

AB║EF

Hence CD║EF

also

CD ║HG

CD║EF

Hence we can come to conclusion that

EF║HG

Hence our answer will be

corresponding segments EF and HG are parallel to each other.

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3 years ago
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