Ill write A for alpha and B for beta.
AB = c/a and A + B = -b/a
A^4 + B^4 = (A^2 + B^2)^2 - 2A^2B^2
= [(A + B)^2 - 2AB] ^2 - 2A^2B^2
Plugging in the values for A+B and AB we get
A^4 + B^4 = [(-b/a)^2 - 2c/a]^2 - 2(c/a)^2
= (b^2 / a^2 - 2c / a)^2 - 2c^2/a^2
= (b^2 - 2ac)^2 - 2c^2
---------------- -----
a^4 a^2
= (b^2 - 2ac)^2 - 2a^2c^2
-----------------------------
a^4
Answer:
it should be true well it has to be
Answer:
y -4 = 1/6(x-24)
y = 1/6x -2
Step-by-step explanation:
We can point slope form
y-y1 = m(x-x1) where m is the slope and (x1,y1) is a point on the line
y -4 = 1/6(x-24)
Or we can write slope intercept form
y = mx+b where m is the slope and b is the y intercept
Substituting the points
4 = 1/6(24)+b
4 = 6+b
4-6 = b
-2 =b
y = 1/6x -2
Answer:
A solution to a system of equations means the point must work in both equations in the system. So, we test the point in both equations. It must be a solution for both to be a solution to the system. Hope this helps.
I think formula is y2-y1 divided by x2-x1 so if im correct
-5/-4
