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Alja [10]
4 years ago
12

What is the eyepiece?

Physics
2 answers:
Yuki888 [10]4 years ago
5 0

Answer:

in a microscope the place you keep your eyes to observe

BigorU [14]4 years ago
4 0

Answer: SOURCE-WIKIPEDIA

An eyepiece, or ocular lens, is a type of lens that is attached to a variety of optical devices such as telescopes and microscopes. It is so named because it is usually the lens that is closest to the eye when someone looks through the device. The objective lens or mirror collects light and brings it to focus creating an image. The eyepiece is placed near the focal point of the objective to magnify this image. The amount of magnification depends on the focal length of the eyepiece. An eyepiece consists of several "lens elements" in a housing, with a "barrel" on one end. The barrel is shaped to fit in a special opening of the instrument to which it is attached. The image can be focused by moving the eyepiece nearer and further from the objective. Most instruments have a focusing mechanism to allow movement of the shaft in which the eyepiece is mounted, without needing to manipulate the eyepiece directly. The eyepieces of binoculars are usually permanently mounted in the binoculars, causing them to have a pre-determined magnification and field of view. With telescopes and microscopes, however, eyepieces are usually interchangeable. By switching the eyepiece, the user can adjust what is viewed. For instance, eyepieces will often be interchanged to increase or decrease the magnification of a telescope. Eyepieces also offer varying fields of view, and differing degrees of eye relief for the person who looks through them.

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maria [59]

Answer:

KE = 100 J

Explanation: Should be correct

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3 years ago
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Natali5045456 [20]

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8 0
3 years ago
Consider the uniform electric field \vec{E} =(4000~\hat{j}+3000~\hat{k})~\text{N/C} ​E ​⃗ ​​ =(4000 ​j ​^ ​​ +3000 ​k ​^ ​​ ) N/
likoan [24]

Answer:

Electric flux \phi=31562.63\ Nm^2/C

Explanation:

Given that,

Electric field acting on the circular area, E=(4000j+3000k)\ N/C

We need to find the electric flux through a circular area of radius 1.83 m that lies in the xy-plane. It lies in xy plane, such that the area vector point in z direction. The electric flux is given by :

\phi=E{\cdot}A

\phi=(4000j+3000k){\cdot}Ak

Using dot product properties, we get the value of electric flux as :

\phi=3000\times Ak

\phi=3000\times \pi (1.83)^2

\phi=31562.63\ Nm^2/C

So, the electric flux through a circular area is \phi=31562.63\ Nm^2/C . Hence, this is the required solution.          

4 0
3 years ago
For an answer to be completed the units need to be specified why?
Setler79 [48]

Answer:

so you know the units in the problem and answer are the same, if they aren't you have to convert them to the same units.

3 0
3 years ago
What is Laminar flow??​
barxatty [35]

Answer:

Explanation:

Laminar Flow is a very important topic discussed in physics in the subject of fluid dynamics. Basically, it explains how fluid particles behave at lower velocities. In such cases and when the viscosity of the fluid is low, the fluid particles flow smoothly in perfectly perpendicular layers that do not collide or cross each other. Unlike turbulent flow, which is the opposite. An example of Laminar flow can be seen when you open up a water hose with little pressure, the water simply flows out of the hose and looks very clear and smooth.

8 0
3 years ago
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