A line would be best used to model the surface of an aquarium, by putting a line on top of the surface and checking if the water is level or not.
If you'd graph this function, you'd see that it's positive on [-1.5,0], and that it's possible to inscribe 3 rectangles on the intervals [-1.5,-1), (-1,-0.5), (-0.5, 1].
The width of each rect. is 1/2.
The heights of the 3 inscribed rect. are {-2.25+6, -1+6, -.25+6} = {3.75,5,5.75}.
The areas of these 3 inscribed rect. are (1/2)*{3.75,5,5.75}, which come out to:
{1.875, 2.5, 2.875}
Add these three areas together; you sum will represent the approx. area under the given curve on the given interval: 1.875+2.5+2.875 = ?
Answer: tysm
Step-by-step explanation:
I needed points to get an answer but didactic have enough
Answer:
1st: volume = long x wide x high = 7 x [sqrt(25^2-7^2)] x 4 = 7 x 24 x 4 = 672
2nd: volume = area of base(circle) x high = pi x 9^2 x 8 = ~ 2035.8
3rd = volume = area of base(triangle) x high = [sqrt(3)/4] x 14^2 x 20 = ~1697.4
12 1/2 because you do 5/6 x 15/1 which 6/3 equals 2 and 15/3 equals 5 so you do 5/2 x 5/1