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lutik1710 [3]
3 years ago
8

Simplify the sum (complex fraction)

Mathematics
2 answers:
andrey2020 [161]3 years ago
5 0
I got 2d^4-2d^2-5/d^2

AVprozaik [17]3 years ago
5 0
The correct answer is 2d - 2
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Which of the following graphs shows the preimage P(x)=x^2 and the image I(x)=P(1/3x)?
Ksju [112]

Answer:

The picture with the widest graph in red

Step-by-step explanation:

The graph P(x) is the parent graph for all quadratic functions. It has a vertex of (0,0) and has the following points:

x      f(x)

-2      4

-1       1

0       0

1         1

2       4

The image of l(x) = P(1/3x) changes the points of the function to

x      f(x)

-2/3      4/9

-1/3        1/9

0       0

1/3        1/9

2/3       4/9

This makes the graph much wider. The graph with the widest red graph is the graph.

7 0
3 years ago
Read 2 more answers
The triangles below are similar because of the:
STALIN [3.7K]

Answer:

ΔABC and  ΔXYZ are SIMILAR by SSS property of similarity.

Step-by-step explanation:

SSS Similarity Theorem:

Two triangles are said to be similar if their  CORRESPONDING SIDES are proportional.

In ΔABC and  ΔXYZ, if \frac{AB}{XY}  = \frac{BC}{YZ} = \frac{AC}{XZ}  , then  △ABC∼△YZX

Here, in ΔABC and  ΔXYZ

AB = 9, BC = x , AC = 12

Similarly, XY = 3, YZ = 2, ZX = 4

Here,

\frac{AB}{XY} = \frac{9}{3}  = 3\\\frac{BC}{YZ} = \frac{x}{2} \\\frac{Ac}{Xz} = \frac{12}{4}  = 3

⇒ Corresponding sides are in the ratio of 3, if BC  =6 units

Hence, if BC  = 6 units, then the ΔABC and  ΔXYZ are SIMILAR by SSS property of similarity.

8 0
3 years ago
Name the intersection of plane acg and plane bcg
cestrela7 [59]
Please attach a photo so I may help you.
8 0
3 years ago
Read 2 more answers
Which could be the dimensions of a rectangular prism whose surface area is greater than 140 square feet? Select three options. 6
Murljashka [212]

Answer:

the second one, ((6 x 5) x 4) +((5 x 4) x 2) = 160

the third one, ((7 x 6) x 4) + (6 x 4) x 2) = 216

the fourth one, ((8 x 4) x 4) + ((4 x 3) x 2) = 152

Step-by-step explanation:

7 0
3 years ago
1/2 ln(x + 3) - lnx = 0 solve for x
rusak2 [61]
1

 

Simplify \frac{1}{2}\imath n(x+3)​2​​1​​ın(x+3) to \frac{\imath n(x+3)}{2}​2​​ın(x+3)​​

\frac{\imath n(x+3)}{2}-\imath nx=0​2​​ın(x+3)​​−ınx=0


2

 

Add \imath nxınx to both sides

\frac{\imath n(x+3)}{2}=\imath nx​2​​ın(x+3)​​=ınx


3

 

Multiply both sides by 22

\imath n(x+3)=\imath nx\times 2ın(x+3)=ınx×2


4

 

Regroup terms

\imath n(x+3)=nx\times 2\imathın(x+3)=nx×2ı


5

 

Cancel \imathı on both sides

n(x+3)=nx\times 2n(x+3)=nx×2


6

 

Divide both sides by nn

x+3=\frac{nx\times 2}{n}x+3=​n​​nx×2​​


7

 

Subtract 33 from both sides

x=\frac{nx\times 2}{n}-3x=​n​​nx×2​​−3


6 0
3 years ago
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