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3 years ago

Which inequality has a closed circle when it is graphed on a number line?

Mathematics

2 answers:

Natalka [10]3 years ago

8 0

Answer:

the answer is D) X _> 3

Step-by-step explanation:

Murljashka [212]3 years ago

5 0

Answer:

the answer is D) X _> 3

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Find the missing number to make these fractions equal. 3/4 = ?/8

babymother [125]

The answer is 6, reaosn is because 6/8 is not simplified, so if we divide both sides by 2 (the numerator and the denominator), we can get a simplified fraction, which is 3/4. Steps: 6/8, 6 divided by 2/8 divided by 2, 3/4.

Hope this helped!

Nate

7 0

3 years ago

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mafiozo [28]

Answer:

1.) x=3 2.)n= -1/4 3.) h=7

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Write an equation of a circle with a center at (2, - 4) and a radius of 4.

fgiga [73]

9514 1404 393

Answer:

(x -2)^2 +(y +4)^2 = 16

Step-by-step explanation:

The equation of a circle with center (h, k) and radius r is ...

(x -h)^2 +(y -k)^2 = r^2

You have (h, k) = (2, -4) and r = 4, so your equation is ...

(x -2)^2 +(y -(-4))^2 = 4^2

(x -2)^2 +(y +4)^2 = 16

6 0

3 years ago

A sum of Rs 1,50,000 amounts to Rs 2,62,500 at a

Naily [24]

Look at the attached picture⤴⤴

Hope this will help u....✔✔:)

3 0

3 years ago

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0

3 years ago