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2 years ago

Please help confused?

Mathematics

2 answers:

coldgirl [10]2 years ago

8 0

All you've got to do is write an equation. EX 2n-1

Anit [1.1K]2 years ago

4 0

Answer:

Formula = 2n-1

Step-by-step explanation:

Given : Antonio uses the power of 2n to find the number of ways bits can be arranged. The n often stands for the number of bits. Millie, collects golden keys to help her in her quest.

To write : A formula to show that Millie can collect one less key than the highest number of bits that can be arranged in the system.

Number of bits =n

Highest number of bits =2n

One less key than the highest number of bits = 2n-1

Therefore, the formula he use = 2n-1

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Find the common ratio 24,18,37/2,81/8

Vinil7 [7]

Note: The third term of the sequence should be $\dfrac{27}{2}$ instead of $\dfrac{37}{2}$ , otherwise the sequence has no common ratio.

Given:

The given sequence is

$24,18,\dfrac{27}{2},\dfrac{81}{8}$

To find:

The common ratio of the given sequence.

Solution:

The quotient of each pair of consecutive terms are:

$\dfrac{18}{24}=\dfrac{3}{4}$

Similarly,

$\dfrac{\dfrac{27}{2}}{18}=\dfrac{27}{36}$

$\dfrac{\dfrac{27}{2}}{18}=\dfrac{3}{4}$

And,

$\dfrac{\dfrac{81}{8}}{\dfrac{27}{2}}=\dfrac{81}{8}\times \dfrac{2}{27}$

$\dfrac{\dfrac{81}{8}}{\dfrac{27}{2}}=\dfrac{3}{4}$

Therefore, the common ratio of the given sequence is $\dfrac{3}{4}$ or 0.75.

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2 years ago

Let A(t) be the area of a circle with radius r(t), at time t in min. Suppose the radius is changing at the rate of drdt=6 ft/min

mylen [45]

Answer:

The rate of change is $108\pi$ ft^(2)/min

Step-by-step explanation:

The area of a circle is given by the following equation:

$A(t) = \pi r^{2}$

To solve this question, we have to realize the implicit differentiation in function of t. We have two variables, A and r. So

$\frac{dA(t)}{dt} = 2\pi r \frac{dr}{dt}$

We have that:

$\frac{dr}{dt} = 6, r = 9$ .

We want to find $\frac{dA}{dt}$

$\frac{dA(t)}{dt} = 2\pi*9*6$

$\frac{dA}{dt} = 108\pi$

Since the area is in square feet, the rate of change is in ft^(2)/min.

So the rate of change is $108\pi$ ft^(2)/min

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2 years ago

Which equation is the equivalent form of 20(3)^5x = 820?

makvit [3.9K]

Answer:

x=ln(41)/ln(243)

Step-by-step explanation:

20(3)^5x=820

3^5x=820/20

3^5x=41

5x=ln(41)/ln(3)

x=(1/5)[ln(41)/ln(3)]

x=ln(41)/ln(3^5)

x=ln(41)/ln(243)

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mestny [16]

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Andre45 [30]

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