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Mandarinka [93]
4 years ago
5

Solve for y. 8/5=4y. Simplify your answe

Mathematics
2 answers:
frozen [14]4 years ago
6 0

Answer:

2/5 =y

Step-by-step explanation:

8/5 = 4y

Divide each side by 4

8/5 * 1/4 = 4y/4

8/4 *1/5 = y

2 *1/5 = y

2/5 =y

Jlenok [28]4 years ago
5 0

Answer:

y=2/5

Step-by-step explanation:

8/5=4y

y=(8/5)/4

y=(8/5)(1/4)

y=8/20

simplify

y=2/5

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If x = 4, what is the value of 2x2 - 7?
Fudgin [204]

Answer:

A) 25

Step-by-step explanation:

I am assuming that you mean: 2x² - 7.

2(4)^2 - 7\\\rule{150}{0.5}\\\rightarrow 2 *4^2 - 7\\\\\rightarrow 2 * 16 - 7\\\\\rightarrow 32 -7\\\\\rightarrow \boxed{25}

5 0
3 years ago
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Bro help please I don’t know that answer I’ll give brainiest
kodGreya [7K]

Answer:

the awnser is 8 as is it it the awnser

5 0
3 years ago
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A confidence interval (CI) is desired for the true average stray-load loss u (watts) for a certain type of induction motor when
Genrish500 [490]

Answer:

A) CI = (57.12 , 59.48)

B) CI = (57.71 , 58.89)

C) CI = (57.53 , 59.07)

D) n = 239.63

Step-by-step explanation:

a)

given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 25Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025,

Zc = Z(α/2) = 1.96

ME = Zc * σ \sqrt{n}

ME = 1.96 * 3 \sqrt{25}

ME = 1.18

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{25} , 58.3 + 1.96 * 3\sqrt{25})

CI = (57.12 , 59.48)

b)

Given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 100

Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025, Zc = Z(α/2) = 1.96

ME = zc * σ \sqrt{n}

ME = 1.96 * 3\sqrt{100}

ME = 0.59

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{100} , 58.3 + 1.96 * 3\sqrt{100})

CI = (57.71 , 58.89)

c)

sample mean, \bar X = 58.3

sample standard deviation, σ = 3

sample size, n = 100

Given CI level is 99%, hence α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005, Zc = Z(α/2) = 2.58

ME = Zc * σ \sqrt{n}

ME = 2.58 * 3\sqrt{100}

ME = 0.77

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 2.58 * 3\sqrt{100} , 58.3 + 2.58 * 3/\sqrt{100}

CI = (57.53 , 59.07)

D)

Given data:

Significance Level, α = 0.01,

Margin or Error, E = 0.5,

σ = 3

The critical value for α = 0.01 is 2.58.

for calculating population mean we used

n \geq (zc *σ/E)^2

n = (2.58 * 3/0.5)^2

n = 239.63

7 0
4 years ago
6/5 s = -2 <br><br> whats the answer solve the (s)
iVinArrow [24]

Answer: s= -5/3

Step-by-step explanation: hope this helps!

7 0
3 years ago
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(a) determine the null and alternative hypotheses, (b) explain what it would mean to make a Type I error, and (c) explain what i
iren2701 [21]
Null: the mean amount of peanut butter in a jar is equal to 32 oz.
alternative: the mean amount of peanut butter in a Jar is less than 32oz.

type 1 error is is rejecting the null when it is actually true. this means that we would say that the mean amount of peanut butter is not equal to 32 when it actually is.

type 2 error is failing to reject the null when it is actually false. this means that we would say the mean amount of peanut butter is equal to 32 when in reality it is less.
3 0
3 years ago
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