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3 years ago

Bro help please I don’t know that answer I’ll give brainiest

Mathematics

2 answers:

aliina [53]3 years ago

7 0

Step-by-step explanation:

It's C.

8x8 = 64,

64/8 = 8

kodGreya [7K]3 years ago

5 0

Answer:

the awnser is 8 as is it it the awnser

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Gnoma [55]

Answer:

Just hope for the best

Step-by-step explanation:

6 0

3 years ago

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Kay is making bead necklaces. She has 80 red beads and 64 blue beads. What is the greatest number of identical necklaces she can

RUDIKE [14]

Answer:

Step-by-step explanation:

80/2 = 40

64/2 = 32

so she can make about 32

3 0

2 years ago

How do I solve #7? do i add all the angles together like a normal triangle and make it equal to 180?

kobusy [5.1K]

Answer:

126 degrees

Step-by-step explanation:

Triangle: y = 180 - (5x + 4x)

Straight angle: y = 180 - (4x + 30)

180 - (5x + 4x) = 180 - (4x + 30)

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y = 180 - 9x

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7 0

3 years ago

A map has a scale of 1 cm : 9 km. If two cities are 2 centimeters apart on the map, what is the actual distance between the citi

Angelina_Jolie [31]

Answer:

18 kilometers

Step-by-step explanation:

If each 1 cm represents 9 kilometers.

How many would 2 cm represent?

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7 0

2 years ago

Find the midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9)

JulsSmile [24]

The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

<u>Solution:</u>

Given, two points are (-6, 6) and (-3, -9)

We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)$ is given by:

$\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

$\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9$

Plugging in the values in formula, we get,

$\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}$

Hence, the midpoint of the segment is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

6 0

3 years ago