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zheka24 [161]
3 years ago
11

6/5 s = -2 whats the answer solve the (s)

Mathematics
2 answers:
iVinArrow [24]3 years ago
7 0

Answer: s= -5/3

Step-by-step explanation: hope this helps!

Katarina [22]3 years ago
3 0

the answer is 5/3 i hope this help!

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Describe the types of transformation given by each parameter in g(x) = -4f(-x + 2) + 6
forsale [732]

Step-by-step explanation:

Starting with f(x)

f(x)

f(-x) ...... reflection in the y - axis

f(-x+2) ..... horizontal translation by 2 units in the negative x-direction

f(-x+2) + 6 ...... vertical translation by 6 units in the positive y-direction

4f(-x+2) + 6 ..... scaling (or dilation) by a factor of 4

-4f(-x+2) + 6 ..... reflection in the x-axis

7 0
4 years ago
Use lagrange multipliers to find the maximum and minimum values of the function subject to the given constraint. f(x,y = xyz; x^
Snezhnost [94]
I'm assuming the constraint involves some plus signs that aren't appearing for some reason, so that you're finding the extrema subject to x^2+2y^2+3z^2=96.

Set f(x,y,z)=xyz and g(x,y,z)=x^2+2y^2+3z^2-96, so that the Lagrangian is

L(x,y,z,\lambda)=xyz+\lambda(x^2+2y^2+3z^2-96)

Take the partial derivatives and set them equal to zero.

\begin{cases}L_x=yz+2\lambda x=0\\L_y=xz+4\lambda y=0\\L_z=xy+6\lambda z=0\\L_\lambda=x^2+2y^2+3z^2-96=0\end{cases}

One way to find the possible critical points is to multiply the first three equations by the variable that is missing in the first term and dividing by 2. This gives

\begin{cases}\dfrac{xyz}2+\lambda x^2=0\\\\\dfrac{xyz}2+2\lambda y^2=0\\\\\dfrac{xyz}2+3\lambda z^2=0\\\\x^2+2y^2+3y^2=96\end{cases}

So by adding the first three equations together, you end up with

\dfrac32xyz+\lambda(x^2+2y^2+3z^2)=0

and the fourth equation allows you to write

\dfrac32xyz+96\lambda=0\implies \dfrac{xyz}2=-32\lambda

Now, substituting this into the first three equations in the most recent system yields

\begin{cases}-32\lambda+\lambda x^2=0\\-32\lambda+2\lambda y^2=0\\-32\lambda+3\lambda z^2=0\end{cases}\implies\begin{cases}x=\pm4\sqrt2\\y=\pm4\\z=\pm4\sqrt{\dfrac23}\end{cases}

So we found a grand total of 8 possible critical points. Evaluating f(x,y,z)=xyz at each of these points, you find that f(x,y,z) attains a maximum value of \dfrac{128}{\sqrt3} whenever exactly none or two of the critical points' coordinates are negative (four cases of this), and a minimum value of -\dfrac{128}{\sqrt3} whenever exactly one or all of the critical points' coordinates are negative.
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3 years ago
WILL GIVE 100 BRAINLY POINTS Instructions
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Answer:

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3 years ago
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Jeremy has 2 less than 3 times the number of Xbox games, x, than Anthony has. Which expression represents the total number of Xb
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3x - 2........................................
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Which of these graphs has its maximum point on the line x=3
Yuliya22 [10]

Answer:

The last graph

Step-by-step explanation:

We are given two tips for finding our graph, it has a max point and the point of the line is x = 3. Meaning that this graph must open down and should not go anything further than 3 on the y graph.

The only one that fits this proposition is the last graph. Making it correct.

8 0
2 years ago
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