Answer:
10/13
Step-by-step explanation:
There are 52 cards in a standard deck. There are 4 queens (queen of spades, clubs, hearts, diamonds) and 36 (2 - 10 of four suites) number cards. Therefore the probability of drawing a queen or a number card is (4 + 36)/52 = 40/52 = 10/13.
Answer: 55
Step-by-step explanation: There is one simple theorem we need to know in order to solve for this.
Triangle Angle-Sum Property: All three angles interior angles of a triangle add up to 180°.
Thus, we could label the points A, B, and C, and set up an algebraic expression.
Let A = 27, B = 98, and C = x.
A + B + C = 180°.
Substituting A, B, and C we get:
27 + 98 + x = 180°.
Adding, we get:
125 + x = 180°
Subtracting 125 by 180, we get:
x = 55°
Thus, the angle X is 55°.
We could have simply solved this by just doing 180 - 98 - 27 = 55 in the first place, but I wanted to show you how I got such results.
2 1/2 - 25 is -24. You just turn the mixed number into an improper fraction and subtract that and 50/2. Hope this helps
Answer:

Step-by-step explanation:
- given ap series : 8,3,-2,-7,-12....up to n terms
[the second term should be +3 or else it wont form AP series]
first term in the series: 8
common difference : 3-8 = -5
total terms : n
- the formula for sum of n terms in an ap =
![\frac{n}{2} [2a+(n-1)d]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B2a%2B%28n-1%29d%5D)
a: first term
d: common difference
n : total terms
- by substituting value in the above formula,
- sum of the A.P:
![\frac{n}{2} [2(8)+(n-1)-5]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B2%288%29%2B%28n-1%29-5%5D)
![\frac{n}{2} [16+(n-1)(-5)]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B16%2B%28n-1%29%28-5%29%5D)
![\frac{n}{2} [16+(n-1)(-5)]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B16%2B%28n-1%29%28-5%29%5D)
![\frac{n}{2} [16+-5n+5]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B16%2B-5n%2B5%5D)
![\frac{n}{2} [21+-5n]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B21%2B-5n%5D)
=
<span>0.75x + 1.5 = 10 is the Answer so B:</span>