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SVEN [57.7K]
4 years ago
10

How are solutions of a polynomial function connected to the graph

Mathematics
1 answer:
DedPeter [7]4 years ago
7 0
The solutions to a polynomial function are all of the points where the line intersects the x-axis.
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Is 64/80 and 20/25 equivalent as ratios
mojhsa [17]
YES!they are equivalent
64/80=4/5
20/25=4/5
4 0
3 years ago
Read 2 more answers
Solve the equation 4(c-3)-8
____ [38]

Answer:

Step-by-step explanation:

6 0
3 years ago
Please help! and thank you so much!
mel-nik [20]

Answer:

  (d)  30 units²

Step-by-step explanation:

The area of the rectangle is the product of the length and width. It is equal to the number of unit squares that fill the rectangle.

__

By counting grid squares or subtracting coordinates, we can see this rectangle is 3 units wide and 10 units high. Its area will be ...

  A = WH

  A = (3 units)(10 units) = 30 units²

_____

<em>Additional comment</em>

You can also count the three columns of 10 shaded squares, or the 10 rows of 3 shaded squares. Either way, you will count 30 square units covering the rectangle.

8 0
2 years ago
how much 45% acid solution should be mixed with a 30% acid solution to make 450 ml of a 40% acid solution?
FromTheMoon [43]
We do as follows:

let x = amount of 45% solution
    y = amount of 30% solution

overall balance =>    x + y = 450
acid balance     =>    .45x + .30y = .40(450)

Solving simultaneously, we will have:

x = 300 mL
y = 150 mL

This is assuming that partial molar properties does not affect the volume greatly. Hope this answers the question. Have a nice day.
7 0
3 years ago
Atul has 2/3 lb of candy. Jose has 3/5 lb and Maria has 1/2 lb less then José. How many more pounds of candy does Atul have than
liraira [26]

Given:

Atul has \dfrac{2}{3} lb of candy.

Jose has \dfrac{3}{5} lb of candy.

Maria has \dfrac{1}{2} lb less than Jose.

To find:

How many more pounds of candy does Atul have than Maria?

Solution:

Since, Maria has \dfrac{1}{2} lb less than Jose, therefore

Maria has = \dfrac{3}{5}-\dfrac{1}{2} lb

Maria has = \dfrac{6-5}{10} lb

Maria has = \dfrac{1}{10} lb

Difference between the candies Atul and Maria have.

Difference = \dfrac{2}{3}-\dfrac{1}{10} lb

Difference = \dfrac{20-3}{30} lb

Difference = \dfrac{17}{30} lb

Therefore,  Atul have \dfrac{17}{30} lb of candy more than Maria.

6 0
3 years ago
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