Answer:
4,330
Step-by-step explanation:
Multiply 21.35 times 200 and you get 4,270, then multiply 200 times 43 and you will get 8,600. then subtract and you will get 4,330
All you do is add 23 and 65 to get your answer <span />
I think the answer is 16x^2+1
Answer:
0.1507 or 15.07%.
Step-by-step explanation:
We have been given that the manufacturing of a ball bearing is normally distributed with a mean diameter of 22 millimeters and a standard deviation of .016 millimeters. To be acceptable the diameter needs to be between 21.97 and 22.03 millimeters.
First of all, we will find z-scores for data points using z-score formula.
, where,
z = z-score,
x = Sample score,
= Mean,
= Standard deviation.



Let us find z-score of data point 22.03.



Using probability formula
, we will get:

Therefore, the probability that a randomly selected ball bearing will be acceptable is 0.1507 or 15.07%.