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jeka94
3 years ago
10

How would I solve these equations?

Mathematics
2 answers:
dmitriy555 [2]3 years ago
5 0
51. X = 1/5, -6 (negative six)

52.  X = 0, -3/2

53.  X = 0, 1/5

54. Z = 0, -7/4
kozerog [31]3 years ago
4 0
51) 5x-1=0 and x+6=0
5x=1, x=1/5 and x=-6
2 solutions x=1/5 and x=-6

52)x(2x+3)=0
2x=0 and 2x+3 =0
x=0   and x=-3/2=-1.5

53) x(5x-1)=0
x=0 and 5x-1=0
x=0 and x=1/5

54) z(4z+7) =0
z=0 and 4z+7=0
z=0 and z= - 7/4 = -1.75
z=0 and z=-1.75
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Plz help me with both questions pllllz
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The differences is 7 because I counted. 
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3 years ago
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BabaBlast [244]

Hello from MrBillDoesMath!

Answer:    y = 2x - 7

Discussion:

Divide both sides of the equation by 2:

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Thank you,

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Answer:

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1.) ???

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vova2212 [387]

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