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jeka94
4 years ago
10

How would I solve these equations?

Mathematics
2 answers:
dmitriy555 [2]4 years ago
5 0
51. X = 1/5, -6 (negative six)

52.  X = 0, -3/2

53.  X = 0, 1/5

54. Z = 0, -7/4
kozerog [31]4 years ago
4 0
51) 5x-1=0 and x+6=0
5x=1, x=1/5 and x=-6
2 solutions x=1/5 and x=-6

52)x(2x+3)=0
2x=0 and 2x+3 =0
x=0   and x=-3/2=-1.5

53) x(5x-1)=0
x=0 and 5x-1=0
x=0 and x=1/5

54) z(4z+7) =0
z=0 and 4z+7=0
z=0 and z= - 7/4 = -1.75
z=0 and z=-1.75
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Zanzabum

Answer:

The domain is (x :  2 < x < 6}

The range is {y : 160 < y < 480}

Step-by-step explanation:

Assume that y is the total charge for x hours

∵ He charges $80 an hour

∵ The number of hours is x

∴ y = 80 x

x is the domain and y is the range

∵ He works between 2 to 6 hours a day

- That means x is between 2 and 6

∴ 2 < x < 6

∵ x represents the domain

∴ The domain is {x : 2 < x < 6}

Lets find the value of y at x = 2 and x = 6 to find the range

∵ x = 2

∴ y = 80(2)

∴ y = 160

∵ x = 6

∴ y = 80(6)

∴ y = 480

- That means y is between 160 and 480

∴ 160 < y < 480

∵ y represents the range

∴ The range is {y : 160 < y < 480}

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3 years ago
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Step-by-step explanation:

7 0
3 years ago
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Step-by-step explanation:

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