Answer:
The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.
Step-by-step explanation:
The question is incomplete. The complete question should be
The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?
Given the initial bearing of a lighthouse from the ship is N 37° E. So, is 37°. We can see from the diagram that would be 143°.
Also, the new bearing is N 25°E. So, would be 25°.
Now we can find . As the sum of the internal angle of a triangle is 180°.
Also, it was given that ship sails 2.5 miles from N 37° E to N 25°E. We can see from the diagram that this distance would be our BC.
And let us assume the distance between the lighthouse and the ship at N 25°E is
We can apply the sine rule now.
So, the distance between the ship at N 25°E and the lighthouse is 7.26 miles.
Answer:
81.4
Step-by-step explanation:
59.2g is for 8, so to find the price per, 59.2/8=7.4. 7.4*11=81.4
Answer:
-12x = 60
Step-by-step explanation:
This is the type of problem that you just have to do a bunch of times until you get it right -- I don't think there's anything I can tell you that'll help you immediately. Ask for your teacher for more exercises of this sort or look it up online.
Good luck!
Use the power, product, and chain rules:
• product rule
• power rule for the first term, and power/chain rules for the second term:
• power rule
Now simplify.
You could also use logarithmic differentiation, which involves taking logarithms of both sides and differentiating with the chain rule.
On the right side, the logarithm of a product can be expanded as a sum of logarithms. Then use other properties of logarithms to simplify
Differentiate both sides and you end up with the same derivative:
Answer:
d??? i think
Step-by-step explanation: