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Delvig [45]
3 years ago
6

A total of $6000 $6000 is invested: part at 8% 8% and the remainder at 13% 13%. how much is invested at each rate if the annual

interest is $650 $650?
Mathematics
1 answer:
liq [111]3 years ago
8 0
0.13x + 0.08(6000-x) = 650 Solve for x
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594 7/25 +89 37/100=
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Hey there!☺

Answer:\boxed{683\frac{13}{20}}

Explanation:

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To solve, we will need to evaluate:

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