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Delvig [45]
3 years ago
6

A total of $6000 $6000 is invested: part at 8% 8% and the remainder at 13% 13%. how much is invested at each rate if the annual

interest is $650 $650?
Mathematics
1 answer:
liq [111]3 years ago
8 0
0.13x + 0.08(6000-x) = 650 Solve for x
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-3(x+2)=6+2x+8 how to solve for x​
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Answer:

         x = - 4

Step-by-step explanation:

-3(x+2)=6+2x+8

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The graph of one complete period of a cosine curve is given.
artcher [175]

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3 years ago
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satela [25.4K]

Hello!

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