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3 years ago

6

A total of $6000 $6000 is invested: part at 8% 8% and the remainder at 13% 13%. how much is invested at each rate if the annual

interest is $650 $650?

1 answer:

liq [111]3 years ago

8 0

0.13x + 0.08(6000-x) = 650 Solve for x

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What is the relationship between the values tand s plotted on the number line

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A. T=s
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2 years ago

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Question 30 of 40

statuscvo [17]

The Reference angle for 302 degree is 58 degree.

<h3 /><h3>What is Reference Angle?</h3>

The acute angle formed by the terminal arm or terminal side and the x-axis is known as the reference angle.

There is always a positive reference angle.

The reference angle is, in other words, the angle formed by the terminal side and the x-axis.

Reference angle is given by

Ф = 360° - Given angle

Ф = 360° - 302°

Ф = 58°

Option A is right answer.

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5 0

11 months ago

Change each of the following points from rectangular coordinates to spherical coordinates and to cylindrical coordinates.

FromTheMoon [43]

Answer and Step-by-step explanation: Spherical coordinate describes a location of a point in space: one distance (ρ) and two angles (Ф,θ).To transform cartesian coordinates into spherical coordinates:

$\rho = \sqrt{x^{2}+y^{2}+z^{2}}$

$\phi = cos^{-1}\frac{z}{\rho}$

For angle θ:

If x > 0 and y > 0: $\theta = tan^{-1}\frac{y}{x}$ ;

If x < 0: $\theta = \pi + tan^{-1}\frac{y}{x}$ ;
If x > 0 and y < 0: $\theta = 2\pi + tan^{-1}\frac{y}{x}$ ;

Calculating:

a) (4,2,-4)

$\rho = \sqrt{4^{2}+2^{2}+(-4)^{2}}$ = 6

$\phi = cos^{-1}(\frac{-4}{6})$

$\phi = cos^{-1}(\frac{-2}{3})$

For θ, choose 1st option:

$\theta = tan^{-1}(\frac{2}{4})$

$\theta = tan^{-1}(\frac{1}{2})$

b) (0,8,15)

$\rho = \sqrt{0^{2}+8^{2}+(15)^{2}}$ = 17

$\phi = cos^{-1}(\frac{15}{17})$

$\theta = tan^{-1}\frac{y}{x}$

The angle θ gives a tangent that doesn't exist. Analysing table of sine, cosine and tangent: θ = $\frac{\pi}{2}$

c) (√2,1,1)

$\rho = \sqrt{(\sqrt{2} )^{2}+1^{2}+1^{2}}$ = 2

$\phi = cos^{-1}(\frac{1}{2})$

$\phi$ = $\frac{\pi}{3}$

$\theta = tan^{-1}\frac{1}{\sqrt{2} }$

d) (−2√3,−2,3)

$\rho = \sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}+3^{2}}$ = 5

$\phi = cos^{-1}(\frac{3}{5})$

Since x < 0, use 2nd option:

$\theta = \pi + tan^{-1}\frac{1}{\sqrt{3} }$

$\theta = \pi + \frac{\pi}{6}$

$\theta = \frac{7\pi}{6}$

Cilindrical coordinate describes a 3 dimension space: 2 distances (r and z) and 1 angle (θ). To express cartesian coordinates into cilindrical:

$r=\sqrt{x^{2}+y^{2}}$

Angle θ is the same as spherical coordinate;

z = z

Calculating:

a) (4,2,-4)

$r=\sqrt{4^{2}+2^{2}}$ = $\sqrt{20}$

$\theta = tan^{-1}\frac{1}{2}$

z = -4

b) (0, 8, 15)

$r=\sqrt{0^{2}+8^{2}}$ = 8

$\theta = \frac{\pi}{2}$

z = 15

c) (√2,1,1)

$r=\sqrt{(\sqrt{2} )^{2}+1^{2}}$ = $\sqrt{3}$

$\theta = \frac{\pi}{3}$

z = 1

d) (−2√3,−2,3)

$r=\sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}}$ = 4

$\theta = \frac{7\pi}{6}$

z = 3

5 0

3 years ago

David wants to pack 574 cereal bars into bags of 10 and bags of 8 the number of bags of 8 is 2 more than the bags of 10. How man

BabaBlast [244]

Answer: Number of bags of 8. = 33

Number of bags of 10. = 31

Step-by-step explanation:

Let x = Number of bags of 8.

y = Number of bags of 10.

As per given.

$8x+10y= 574$ (i)

$x=y+2$ (ii)

Put value of x from (ii) in (i)

$8(y+2)+10y= 574\\\\\Rightarrow\ 8y+16+10y=574\\\\\Rightarrow\ 18y=574-16\\\\\Rightarrow\ 18y=558\\\\\Rightarrow\ y=\dfrac{558}{18}\\\\\Rightarrow\ y=18$

Put this in (i), x= 31+2=33

Hence,

Number of bags of 8. = 33

Number of bags of 10. = 31

6 0

2 years ago