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3 years ago

6

A total of $6000 $6000 is invested: part at 8% 8% and the remainder at 13% 13%. how much is invested at each rate if the annual

interest is $650 $650?

1 answer:

liq [111]3 years ago

8 0

0.13x + 0.08(6000-x) = 650 Solve for x

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C is the correct answer

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3 years ago

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mash [69]

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First, arrange the data giving in ascending order. That is

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Step-by-step explanation:

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