D because some of the inputs have the same output therefor it is not a function
Answer:
18
Step-by-step explanation:
multiply 7 and 3
reduce 15/5 to 3
subtract 21-3
18
Answer:
Step-by-step explanation:
1. You must clear the absolute value bars.
2. You have two cases: a positive case and a negative case.
3. First, you can solve the positive case as following:
4. Now, you must solve thie negative case as you can see below:
5. Therefore, the answer is:
<span>2≤x≤8</span>
<span>−4≤<span>f′</span>(x)≤5</span>
f is continuous in differentable on [2,8] so we know there is c btw 2 and 8 such that
<span><span>f′</span>(c)=<span><span>f(8)−f(2)</span><span>/8−2</span></span></span>
And we know
<span>−4≤<span>f′</span>(c)≤5</span>
=> we have
<span>−4≤ <span><span>f(8)−f(2)</span><span>/8−2</span></span> ≤<span>5</span></span>
Answer:
1. 5(3x - 2) = 15x - 10
2. 2x(6x + 5) = 12x + 10
3. 2x/3(9x + 6) = 6x^2 + 4x
