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3 years ago

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At store 1 I can buy 36oz of baby formula for $26.62,and at store 2 I can buy 28oz of baby formula for $22.42. Which one is the

better buy and by how much

1 answer:

a_sh-v [17]3 years ago

7 0

There is a 8oz difference, and a $4.20 difference, causing store 1 to be the better deal

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Write the following sum using summation notation -2/5+3/6-4/7........11/14

horrorfan [7]

Answer:

$\sum_{n=1}^{10}(-1)^n\left ( \frac{n+1}{n+4} \right )$

Step-by-step explanation:

Given: $\frac{-2}{5}+\frac{3}{6}-\frac{4}{7}+...+\frac{11}{14}$

To write: the given expression using summation notation

Solution:

Summation notation helps to write a long sum as a single expression.

In the summation notation, the variable $\sum$ is called the index of summation.

Let $x_1,x_2,x_3,...,x_n$ denote a set of n numbers.

Then in summation notation,

$x_1+x_2+x_3+...+x_n=\sum_{i=1}^{n}x_i$

$\frac{-2}{5}=(-1)^1\left ( \frac{1+1}{1+4} \right )\\\frac{3}{6}=(-1)^2\left ( \frac{2+1}{2+4} \right )\\\frac{-4}{7}=(-1)^3\left ( \frac{3+1}{3+4} \right )\\.\\.\\.\\\frac{11}{14}=(-1)^10\left ( \frac{10+1}{10+4} \right )\\\therefore \frac{-2}{5}+\frac{3}{6}-\frac{4}{7}+...+\frac{11}{14}=\sum_{n=1}^{10}(-1)^n\left ( \frac{n+1}{n+4} \right )$

3 0

3 years ago

2 1/2 yards the cost was 15$ cost per yard

grigory [225]

15 + 15 + 7.50 equals $37.50

6 0

3 years ago

Read 2 more answers

A pail holds 4 1/4 gallons of water. How much is this in cups?

Oliga [24]

16 cups in 1 gallon so multiply 4 1/4 x 16 =68 cups

6 0

2 years ago

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john had thrice as many stickers as Ken. After Ken had given away 12 stickers to his brother, John had 5 times as many stickers

postnew [5]

The number of stickers John and Ken have in the end is 6 and 18 respectively.

<h3>How to write and solve equation?</h3>

let

Ken stickers = x
John stickers =3x

New stickers

Ken = x - 12
John = 5x

x + x - 12 = 3x + 5x

2x - 12 = 8x

-12 = 8x - 6x

-12 = -2x

x = 12/2

x = 6

So,

Ken stickers = x

= 6 stickers

John stickers = 3x

= 3 × 6

= 12 stickers

Learn more about equation:

brainly.com/question/1214333

5 0

2 years ago

A large operator of timeshare complexes requires anyone interested in making a purchase to first visit the site of interest. His

morpeh [17]

Answer:

There is a 21.053% probability that this person made a day visit.

There is a 39.474% probability that this person made a one night visit.

There is a 39.474% probability that this person made a two night visit.

Step-by-step explanation:

We have these following percentages

20% select a day visit

50% select a one-night visit

30% select a two-night visit

40% of the day visitors make a purchase

30% of one night visitors make a purchase

50% of two night visitors make a purchase

The first step to solve this problem is finding the probability that a randomly selected visitor makes a purchase. So:

$P = 0.2(0.4) + 0.5(0.3) + 0.3(0.5) = 0.38$

There is a 38% probability that a randomly selected visitor makes a purchase.

Now, as for the questions, we can formulate them as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

Suppose a visitor is randomly selected and is found to have made a purchase.

How likely is it that this person made a day visit?

What is the probability that this person made a day visit, given that she made a purchase?

P(B) is the probability that the person made a day visit. So $P(B) = 0.20$

P(A/B) is the probability that the person who made a day visit made a purchase. So $P(A/B) = 0.4$

P(A) is the probability that the person made a purchase. So $P(A) = 0.38$

So

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.4*0.2}{0.38} = 0.21053$

There is a 21.053% probability that this person made a day visit.

How likely is it that this person made a one-night visit?

What is the probability that this person made a one night visit, given that she made a purchase?

P(B) is the probability that the person made a one night visit. So $P(B) = 0.50$

P(A/B) is the probability that the person who made a one night visit made a purchase. So $P(A/B) = 0.3$

P(A) is the probability that the person made a purchase. So $P(A) = 0.38$

So

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.5*0.3}{0.38} = 0.39474$

There is a 39.474% probability that this person made a one night visit.

How likely is it that this person made a two-night visit?

What is the probability that this person made a two night visit, given that she made a purchase?

P(B) is the probability that the person made a two night visit. So $P(B) = 0.30$

P(A/B) is the probability that the person who made a two night visit made a purchase. So $P(A/B) = 0.5$

P(A) is the probability that the person made a purchase. So $P(A) = 0.38$

So

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.3*0.5}{0.38} = 0.39474$

There is a 39.474% probability that this person made a two night visit.

3 0

3 years ago