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VARVARA [1.3K]
2 years ago
14

Please help! Will mark brainless​

Mathematics
2 answers:
KengaRu [80]2 years ago
4 0
Here’s what you can do to make this very simple. Consider that the “missing” space between the rectangles isn’t there. Then, find the area:

10 x 9 = 90 mm

Now, find the area of the “missing” part.

5 x 2 = 10 mm

Finally, you deduct the missing part from the complete rectangle!

90 - 10 = 80 mm

The area of this whole thing is 80 mm!

HACTEHA [7]2 years ago
4 0

Answer:

A_{total} = 80\ mm^2

Step-by-step explanation:

<u>Step 1:  Determine the area of the bottom rectangle</u>

A = l * w

A = (9\ mm) * (10\ mm - 5\ mm)

A = 9\ mm * 5\ mm

A = 45\ mm^2

<u>Step 2:  Determine the area of the top rectangle</u>

A = l * w

A = (9\ mm - 2\ mm) * (5\ mm)

A = 7\ mm * 5\ mm

A = 35\ mm^2

<u>Step 3:  Determine the total area</u>

A_{total} = 45\ mm^2 + 35\ mm^2

A_{total} = 80\ mm^2

Answer: A_{total} = 80\ mm^2

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Complete question is;

An automobile manufacturer is concerned about a possible recall of its best - selling four-door sedan. If there were a recall, there is a probability of 0.25 of a defect in the brake system, 0.18 of a defect in the transmission, 0.17 of a defect in the fuel system, and 0.40 of a defect in some other area.

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(b) What is the probability that there are no defects in either the brakes or the fueling system?

Answer:

A) 0.27

B) 0.73

Step-by-step explanation:

Let B denote that there is a defect in the break system

Let T demote that there is a defect in transmission

Let F denote that there is a defect in the fuel system.

Let P denote that there is a defect in some other area.

Now, we are given;

P(B) = 0.25

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A) We are given that probability of defects in both brakes and the fueling system simultaneously is 0.15.

Thus, it means; P(B ⋂ F) = 0.15

Now, we want to find the probability that the defect is the brakes or the fueling system. This is expressed as;

P(B ⋃ F) = P(B) + P(F) - P(B ⋂ F)

Plugging in the relevant values to give;

P(B ⋃ F) = 0.25 + 0.17 - 0.15

P(B ⋃ F) = 0.27

B) We want to find the probability that there are no defects in either the brakes or the fueling system.

This is expressed as;

P(B' ⋃ F') = 1 - P(B ⋃ F)

Plugging in relevant value;

P(B' ⋃ F') = 1 - 0.27

P(B' ⋃ F') = 0.73

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