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VARVARA [1.3K]
2 years ago
14

Please help! Will mark brainless​

Mathematics
2 answers:
KengaRu [80]2 years ago
4 0
Here’s what you can do to make this very simple. Consider that the “missing” space between the rectangles isn’t there. Then, find the area:

10 x 9 = 90 mm

Now, find the area of the “missing” part.

5 x 2 = 10 mm

Finally, you deduct the missing part from the complete rectangle!

90 - 10 = 80 mm

The area of this whole thing is 80 mm!

HACTEHA [7]2 years ago
4 0

Answer:

A_{total} = 80\ mm^2

Step-by-step explanation:

<u>Step 1:  Determine the area of the bottom rectangle</u>

A = l * w

A = (9\ mm) * (10\ mm - 5\ mm)

A = 9\ mm * 5\ mm

A = 45\ mm^2

<u>Step 2:  Determine the area of the top rectangle</u>

A = l * w

A = (9\ mm - 2\ mm) * (5\ mm)

A = 7\ mm * 5\ mm

A = 35\ mm^2

<u>Step 3:  Determine the total area</u>

A_{total} = 45\ mm^2 + 35\ mm^2

A_{total} = 80\ mm^2

Answer: A_{total} = 80\ mm^2

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Find T5(x) : Taylor polynomial of degree 5 of the function f(x)=cos(x) at a=0 . (You need to enter function.) T5(x)= Find all va
Burka [1]

Answer:

\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}

The polynomial is an approximation with an error less than or equals to <em>0.002652</em> for x in the interval

[-1.113826815, 1.113826815]

Step-by-step explanation:

According to Taylor's theorem

\bf f(x)=f(0)+f'(0)x+f''(0)\displaystyle\frac{x^2}{2}+f^{(3)}(0)\displaystyle\frac{x^3}{3!}+f^{(4)}(0)\displaystyle\frac{x^4}{4!}+f^{(5)}(0)\displaystyle\frac{x^5}{5!}+R_6(x)

with

\bf R_6(x)=f^{(6)}(c)\displaystyle\frac{x^6}{6!}

for some c in the interval (-x, x)

In the particular case f

<em>f(x)=cos(x) </em>

<em> </em>

we have

\bf f'(x)=-sin(x)\\f''(x)=-cos(x)\\f^{(3)}(x)=sin(x)\\f^{(4)}(x)=cos(x)\\f^{(5)}(x)=-sin(x)\\f^{(6)}(x)=-cos(x)

therefore

\bf f'(x)=-sin(0)=0\\f''(0)=-cos(0)=-1\\f^{(3)}(0)=sin(0)=0\\f^{(4)}(0)=cos(0)=1\\f^{(5)}(0)=-sin(0)=0

and the polynomial approximation of T5(x) of cos(x) would be

\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}

In order to find all the values of x for which this approximation is within 0.002652 of the right answer, we notice that

\bf R_6(x)=-cos(c)\displaystyle\frac{x^6}{6!}

for some c in (-x,x). So

\bf |R_6(x)|\leq|\displaystyle\frac{x^6}{6!}|=\displaystyle\frac{|x|^6}{6!}

and we must find the values of x for which

\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652

Working this inequality out, we find

\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652\Rightarrow |x|^6\leq1.90944\Rightarrow\\\\\Rightarrow |x|\leq\sqrt[6]{1.90944}\Rightarrow |x|\leq1.113826815

Therefore the polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

8 0
3 years ago
34566+986994689999999
Jlenok [28]

Answer:

9.8699469e+14 and/or 986994690000000

Step-by-step explanation:


4 0
3 years ago
You start at (3, 0). You move down 5 units and right 1 unit. Where do you end?
nevsk [136]

Answer:

Pretty sure it's (4, -5)

Step-by-step explanation:

If not, shoot me I guess.

8 0
3 years ago
Georgia has a budget of $8 for a new notebook. She wants to spend within $5 of her budget, so she uses the equation 5 = |8 – x|
siniylev [52]

Answer:

Minimum: 3

Maximum: 13

Step-by-step explanation:

Georgia uses the equation

5 = |8 – x| to find the maximum and minimum values.

We solve the equation for x.

5 =  |8 - x|

By the definition of the absolute value function, we must have:

- 5 = 8 - x \: or \: 5 = 8 - x

We subtract 8 from both sides to get:

- 5 - 8 =  - x \: or \: 5 - 8 =  - x

- 13 =  - x \: or \:  - 3 =  - x

This simplifies to:

13 =  x \: or \:  3 = x

Therefore the minimum value is 3 and maximum is 13

5 0
3 years ago
yuson must complete 30 hours of community service. she does 2 hours each day. which linear equation represents the hours yuson h
algol [13]

Answer:

30-2x

Step-by-step explanation:

yuson has to finish am total of 30 hours in community service

she does 2 hours each day

in x days, hour of service done=2x

after x days hours of service left=30-2x

therefore the linear equation representing the hours yuson has left after x days is:

30-2x

6 0
2 years ago
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