Answer:
2:8
25:100
5:20
1.25:5
Step-by-step explanation:
In the standard form of the equation
![\\ \ f(t)=Acos[b(t\pm c)]+k\\ \\](https://tex.z-dn.net/?f=%20%5C%5C%20%5C%20f%28t%29%3DAcos%5Bb%28t%5Cpm%20c%29%5D%2Bk%5C%5C%20%5C%5C%20)
The middle line =k
For our given problem
f(t) = 40cos (80t + 20)
On comparison we get k=0
Hence middle line=0
Answer and Step-by-step explanation:
The parent function, f(x) = |x|, has no transformations applied to it.
When the number is with the x, it translates the graph horizontally. <->
When the number is outside of the absolute box, it translates the graph vertically. ^ V
When the number is multiply the absolute box on the outside with the x inside, it scales the graph.
So, first lets apply the translations of horizontal and vertical shift.
The graph translated 1 units downwards.
The graph translates 2 units to the right.
g(x) = |x - 2| - 1
We subtract the 2 because that makes it go right, while if we added it would go left.
Now for the scale.
The lines have a slope of
, so that is what we are multiplying.
<u> g(x) = </u>
<u>|x - 2| - 1</u>
<u></u>
<u>^That is your transformed function.</u>
<u></u>
<u></u>
<u></u>
<em><u>#teamtrees #PAW (Plant And Water)</u></em>
Answer: Option B
B. 
Step-by-step explanation:
We have the following equations:
(1)
(2)
Let us call "a" the coefficient of the variable x in the first equation and call "b" the coefficient of the variable x in the second equation.
Then we must multiply the number "a" by a value z such that when adding
the result is zero.

So

We solve the equation for z


The first equation must be multiplied by a value of 
I attached a pic with my work on it. Hope this helps!